Qualification > Sciences

P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE

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halosh92:

--- Quote from: *Hope* on June 05, 2010, 09:13:26 pm ---q5ai: u actually find the exact point and sub in the equation R=V/I
simply at 6v, the current is 40mA but u have to convert it to Amperes so 40*10^-3
the final ans is 150

4b: for i1...it is just guessing but as the ms said: 0.3mm to 3mm

i2 the general formula is x=Dh/a

bii1: as x is the seperation. if u double the D in the eq, the x will double so the separation increases
maximum brightness will be less cuz u r increasing the distance of the light to the screen so there will be less light reaching and so less max brightness

bii2: again as h is increased so if u sub in the eq , the x will increase
the max brightness will decrese..am not sure though of the reason..but as the h increases the frequency decreases so as intensity is A^2 or f^2, the intensity will decrease

bii3:as all r kept constant the x will remain constant which is the seperation
the maximum brightness increases as the intensity increases

Hope i helped and was clear... :)

--- End quote ---

that was very helpful thanku so much :D

*Hope*:

--- Quote from: halosh92 on June 05, 2010, 09:21:29 pm ---that was very helpful thanku so much :D

--- End quote ---
np..glad to help ;)

Meticulous:
I AM VERY VERY SORRY HALOSH ;D

HAD NET PROBLEMS ;D

THANKS HOPE! :D +rep.!

halosh92:

--- Quote from: ~ A.F ~ on June 05, 2010, 09:29:42 pm ---I AM VERY VERY SORRY HALOSH ;D

HAD NET PROBLEMS ;D

THANKS HOPE! :D +rep.!

--- End quote ---

np A.F ure always helpful ;)

*Hope*:

--- Quote from: ~ A.F ~ on June 05, 2010, 09:29:42 pm ---I AM VERY VERY SORRY HALOSH ;D

HAD NET PROBLEMS ;D

THANKS HOPE! :D +rep.!

--- End quote ---
Thanks A.F :)

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