Qualification > Sciences
P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
halosh92:
--- Quote from: *Hope* on June 05, 2010, 08:12:42 pm ---actually if u notice that a right angle triangle can be formed from the those two lines
the radius is 3\2 which is equal to 1.5
this will be the hyp of a right angle triangle
so the angle 6.5 can be used to find the opp of the triangle which will be the extension
so sin6.5*1.5 will be the extension(opp)
--- End quote ---
thx... ;) my head would break if something like this comes in the exam..how the hell r we supposed to think of this >:(
zxcvbnm:
x=yD/a
where x is the fringe separation, y is the wavelength, D is distance between slits and screen and a is slit separation.
please explain the effects on intensity of changing y,D and a....for y and D, i know that the intensity changes, but for a, the intensity remains the same....why is that?
*Hope*:
--- Quote from: halosh92 on June 05, 2010, 08:19:09 pm ---thx... ;) my head would break if something like this comes in the exam..how the hell r we supposed to think of this >:(
--- End quote ---
haha..I know!! I got it as a quiz once!! And omg!!! I just stoppped thinking!!lool!! But insA no worries hopefully nothing will come like this in the exam :)
halosh92:
yes exactly nshalla we should pray ;D
same paper another question
Q5ai
its not a straight line so shouldnt we draw a tangent here?
and could u explain Q4b
*Hope*:
--- Quote from: halosh92 on June 05, 2010, 08:53:19 pm ---yes exactly nshalla we should pray ;D
same paper another question
Q5ai
its not a straight line so shouldnt we draw a tangent here?
and could u explain Q4b
--- End quote ---
q5ai: u actually find the exact point and sub in the equation R=V/I
simply at 6v, the current is 40mA but u have to convert it to Amperes so 40*10^-3
the final ans is 150
4b: for i1...it is just guessing but as the ms said: 0.3mm to 3mm
i2 the general formula is x=Dh/a
bii1: as x is the seperation. if u double the D in the eq, the x will double so the separation increases
maximum brightness will be less cuz u r increasing the distance of the light to the screen so there will be less light reaching and so less max brightness
bii2: again as h is increased so if u sub in the eq , the x will increase
the max brightness will decrese..am not sure though of the reason..but as the h increases the frequency decreases so as intensity is A^2 or f^2, the intensity will decrease
bii3:as all r kept constant the x will remain constant which is the seperation
the maximum brightness increases as the intensity increases
Hope i helped and was clear... :)
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