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Author Topic: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE  (Read 18100 times)

Offline astarmathsandphysics

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #120 on: June 07, 2010, 10:42:24 pm »
nov 09
7ai)R
ii)R/2 since BY is in paralell with CX
iii)R+R/2+R since AB is in series with YZ and the paralell circuit between Band Y
bi)I_1+I_2=I_3
ii)E_=I_1 R+I_2 R by applying V=IR to the two resistances
iii)E_1-E_2 =I_1 R -I_2 R +I_1 R
net voltage is E_1 -E_2 and apply V=IR to each (remeber I_2 is in opposite direction so negative)
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Offline Chingoo

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #121 on: June 07, 2010, 11:02:36 pm »
Thanks a lot!
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All that is on earth will perish:
But will abide (forever) the Face of thy Lord--full of Majesty, Bounty & Honor.
Then which of the favors of your Lord will ye deny?

Qura'n, Chapter 55: The Beneficent, Verses 26-28

Offline hesho21

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #122 on: June 07, 2010, 11:51:26 pm »
Guys plz Nov 07 , 4c , I dont get the bubble thing at all !
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Offline astarmathsandphysics

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #123 on: June 07, 2010, 11:59:32 pm »
breaking stress=9.5*10^7=F/A=1900/A so A=1900/9.5*10^9=2*10^-6 =actuall cross section of metal
3.2*10^-6-2*10^-6=1.2*10^-6=cross section of bubble
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Offline hesho21

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #124 on: June 08, 2010, 12:10:48 am »
Quote from: astarmathsandphysics on June 07, 2010, 11:59:32 pm
breaking stress=9.5*10^7=F/A=1900/A so A=1900/9.5*10^9=2*10^-6 =actuall cross section of metal
3.2*10^-6-2*10^-6=1.2*10^-6=cross section of bubble


can i ask why did u subtract at the end the areas?
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Offline sweetie

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #125 on: June 08, 2010, 12:11:55 am »
Quote from: astarmathsandphysics on June 07, 2010, 10:25:38 pm
m/j 2006 7 a b c
if the lamp that shorted is C
so shouldnt the resistance of one of the normal lamps be 30?
no is 15 cos when S_1 is closed and other two open Resistance is 15

i still dont get it
cud u plz xplain it again in more detail?
Thank You soooo much :)
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Offline thecandydoll

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #126 on: June 08, 2010, 04:13:32 am »
Could anyone solve this one with diagram =)
Oct/Nov/2009 Variant 22.
Q3--alll =(
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Offline The SMA

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #127 on: June 08, 2010, 04:29:36 am »
can somebody help me on M/J 2004 p2 Q8abc please
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Offline cashem'up

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #128 on: June 08, 2010, 07:39:58 am »
Quote from: The SMA on June 08, 2010, 04:29:36 am
can somebody help me on M/J 2004 p2 Q8abc please

theres a formula u should be aware with chek pg 188 of chris mee physics textbook
Vout= VR1 / (R1 + R2)
ok  now lets use it here

a) 1.0= 1.5 R1/ (R1 + 3900)
1.0R1+3900=1.5R1
0.5R1=3900
R1=7800

b)Vout= 1.5x7800 / 1250+7800 = 1.293 V

c)the  voltmeter has 7800 V so parallel voltage is 7800/2 = 3900
now Vout = 1.5x3900 / 3900+3900 = 0.75V
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Offline sabrina

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #129 on: June 08, 2010, 09:00:03 am »
hi guys
physics tomorrow  :'( and im going crazy. someone plz explain m/j2009 var1 q5a. shouldn't it be inphase?
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Offline sabrina

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #130 on: June 08, 2010, 09:02:17 am »
n the next too
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Offline halosh92

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #131 on: June 08, 2010, 09:03:42 am »
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everyday we wake up is a miracle, then how do we say miracles dont happen?????

Offline sabrina

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #132 on: June 08, 2010, 09:07:04 am »
here it is
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Offline halosh92

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #133 on: June 08, 2010, 09:09:32 am »
Quote from: sabrina on June 08, 2010, 09:07:04 am
here it is

for part a) this is a repeated question and the answer is always the same , its a fact just learn wats in the ms.
and for the next question, it solved somewhere in this thread by "nid" just look for it in the previous pages.
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everyday we wake up is a miracle, then how do we say miracles dont happen?????

Offline sabrina

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #134 on: June 08, 2010, 09:11:49 am »
thanks i will just check it
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