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chem 21 Discussion
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Topic: chem 21 Discussion (Read 1193 times)
sweetie
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chem 21 Discussion
«
on:
June 01, 2010, 01:03:33 pm »
so, i guess 24 hrs have passed, lets discuss da paper!!!
lemme start, wat waz the ans. 4 how many COOH were in the polycarboxylic acid?
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amrgo
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Re: chem 21 Discussion
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Reply #1 on:
June 01, 2010, 03:00:13 pm »
I GOT IT 2 carbooxylic acid as so 3/4 of my friends got it 2
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leebux101
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Re: chem 21 Discussion
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Reply #2 on:
June 01, 2010, 03:21:26 pm »
yup i got 2 carboxylic acid groups too!
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moon
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Re: chem 21 Discussion
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Reply #3 on:
June 01, 2010, 06:01:48 pm »
ya, I wrote it the same 2 carboxylic acid.
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sweetie
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Re: chem 21 Discussion
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Reply #4 on:
June 01, 2010, 06:04:42 pm »
me too i got 2
nd wat did u write for why reaction 1 needs heat while 2 doesnt???
i wrote because the hal. alkane had stronger induced dipole forces than HCl because it has a higher proton no.
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Last Edit: June 01, 2010, 06:06:58 pm by sweetie
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ketone
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Re: chem 21 Discussion
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Reply #5 on:
June 04, 2010, 12:20:24 pm »
u r rite sweetie
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leebux101
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Re: chem 21 Discussion
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Reply #6 on:
June 04, 2010, 03:23:11 pm »
i wrote abt intermediate compounds and activation energy...
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chem 21 Discussion