Author Topic: Add Maths June 8, 10 2010  (Read 14356 times)

Offline ankitd_1994

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Add Maths June 8, 10 2010
« on: May 29, 2010, 11:40:16 am »
hey can anyone who is an ex add math student or doing add math this yr, post up a list of formuale and short notes on all chapters for add math?? ???

Offline theaguia

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Re: Add Maths June 8, 10 2010
« Reply #1 on: May 29, 2010, 12:09:38 pm »
hey can anyone who is an ex add math student or doing add math this yr, post up a list of formuale and short notes on all chapters for add math?? ???

i am doing, i havent studied for any other exam except add math, the hardest exam of em all, an i have eco on the same day. its bad, By the way just post doubts i reqally cant have notes for maths

Offline J.Darren

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Re: Add Maths June 8, 10 2010
« Reply #2 on: May 29, 2010, 05:39:56 pm »
Arc length : theta (in radian) x radius
Sector area : 1/2 x theta (in radian) x radius^2
Do not go where the path may lead. Go instead where there is no path and leave a trail.

Offline jellybeans

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Re: Add Maths June 8, 10 2010
« Reply #3 on: May 29, 2010, 05:41:39 pm »
heyeyyyy, does anybody have notes for bearings & stuff? :( like finding the.. velocity .. vectors.. and.. stuff? :/
You said I must eat so many lemons cause I am so bitter.

Offline adrian1993

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Re: Add Maths June 8, 10 2010
« Reply #4 on: May 29, 2010, 06:48:34 pm »
Relative velocity seems to be the hardest imo.

Offline jellybeans

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Re: Add Maths June 8, 10 2010
« Reply #5 on: May 30, 2010, 02:24:46 am »
Relative velocity seems to be the hardest imo.

i agreeeeeee  :'( :'( :'( hahah.
You said I must eat so many lemons cause I am so bitter.

Offline theaguia

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Re: Add Maths June 8, 10 2010
« Reply #6 on: May 30, 2010, 07:50:42 am »
heyeyyyy, does anybody have notes for bearings & stuff? :( like finding the.. velocity .. vectors.. and.. stuff? :/

just post a question

Offline jellybeans

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Re: Add Maths June 8, 10 2010
« Reply #7 on: May 30, 2010, 08:30:19 am »
just post a question

HIIII, lol. could you see what i did .. wrong please? :/
You said I must eat so many lemons cause I am so bitter.

Offline theaguia

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Re: Add Maths June 8, 10 2010
« Reply #8 on: May 30, 2010, 09:28:33 am »
HIIII, lol. could you see what i did .. wrong please? :/

from first impression it looks like ur diagram is wrong, but i will do the question and get back to you

Offline jellybeans

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Re: Add Maths June 8, 10 2010
« Reply #9 on: May 30, 2010, 09:30:04 am »
from first impression it looks like ur diagram is wrong, but i will do the question and get back to you
LOL hahahahahahaha, aite XD
You said I must eat so many lemons cause I am so bitter.

Offline J.Darren

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Re: Add Maths June 8, 10 2010
« Reply #10 on: May 30, 2010, 10:37:31 am »
Rules of Differntiation :

x^n = nx^(n-1)
e^2x = 2e^2x
ln x = 1 / x
sin x = cos x
cos x = -sin x
tan x = sec^2 x

Chain rule (Composite function):

y = ln (2x + 1)

y = ln (u)
u = 2x + 1

dy/du = 1/u
du/dx = 2

dy/du x du/dx = dy/dx

1/(2x + 1) * 2 = 2/(2x + 1)

Quotient rule :

y = u / v

dy/dx = (vu' - v'u) / v^2

Product rule (Multiple functions):

y = u x v

dy/dx = v'u + u'v

y = 3x^2 x e^x

v = 3x^2
u = e^x

v' = 6x
u' = e^x

dy/dx = 6xe^x + 3x^2e^x
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Offline J.Darren

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Re: Add Maths June 8, 10 2010
« Reply #11 on: May 30, 2010, 11:05:23 am »
Second derivative :

If smaller than 0 - Maximum
If equals to 0 - Point of inflexion
If greater than 0 - Minimum

Rules of Integration :

e^2x = 1/2 x e^2x
cos ax = 1/a x sin x
sin ax = 1/a x -cos x

Add constant c when integrating an indefinite integral

x^n = [x^(n+1)]/(n+1)

(ax+b)^n = [(ax+b)^n+1]/[a*(n+1)]

1/(ax+b) = [ln(ax+b)]/a
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Offline J.Darren

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Re: Add Maths June 8, 10 2010
« Reply #12 on: May 30, 2010, 11:18:18 am »
Solving simultaneous equation using matrices :

AX = C
A–1 AX = A–1C
IX = A–1 C
X = A–1 C

Finding the inverse of a 2 x 2 matrix :



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Offline cooldude

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Re: Add Maths June 8, 10 2010
« Reply #13 on: May 30, 2010, 11:36:18 am »
HIIII, lol. could you see what i did .. wrong please? :/

see the question is  basically asking what is the time taken for the boat to travel the dist AC, dist BC=54 because the speed of the liner is 36 km/h and the time it travels is 1.5 hrs thus the dist=1.5*36=54, the dist AC can be found out by the cosine rule, x=angle ABC
A^2=B^2+C^2-2ABcosx
A^2=90^2+54^2-(2*54*90*cos 135)
A=AC=133.75 km
therefore the speed of the boat = 133.75/1.5=89.2 km/h


Offline Ghost Of Highbury

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Re: Add Maths June 8, 10 2010
« Reply #14 on: May 30, 2010, 11:54:41 am »
isnt it 28.9 km/h?
divine intervention!