« previous next »
Pages: [1]   Go Down

Author Topic: chem 21 Discussion  (Read 1235 times)

Offline sweetie

  • SF Citizen
  • ***
  • Posts: 286
  • Reputation: 258
  • Gender: Female
chem 21 Discussion
« on: June 01, 2010, 01:03:33 pm »
so, i guess 24 hrs have passed, lets discuss da paper!!!

lemme start, wat waz the ans. 4 how many COOH were in the polycarboxylic acid????
Logged

Offline amrgo

  • Newbie
  • *
  • Posts: 7
  • Reputation: 9
  • Gender: Male
Re: chem 21 Discussion
« Reply #1 on: June 01, 2010, 03:00:13 pm »
I GOT IT 2 carbooxylic acid as so 3/4 of my friends got it 2 :D
Logged

Offline leebux101

  • SF Geek
  • ****
  • Posts: 495
  • Reputation: 2966
Re: chem 21 Discussion
« Reply #2 on: June 01, 2010, 03:21:26 pm »
yup i got 2 carboxylic acid groups too!
Logged

Offline moon

  • SF Citizen
  • ***
  • Posts: 222
  • Reputation: 770
Re: chem 21 Discussion
« Reply #3 on: June 01, 2010, 06:01:48 pm »
ya, I wrote it the same 2 carboxylic acid.
Logged

Offline sweetie

  • SF Citizen
  • ***
  • Posts: 286
  • Reputation: 258
  • Gender: Female
Re: chem 21 Discussion
« Reply #4 on: June 01, 2010, 06:04:42 pm »
me too i got 2  :)

nd wat did u write for why reaction 1 needs heat while 2 doesnt???
i wrote because the hal. alkane had stronger induced dipole forces than HCl because it has a higher proton no.?????? ::)
« Last Edit: June 01, 2010, 06:06:58 pm by sweetie »
Logged

Offline ketone

  • SF Immigrant
  • **
  • Posts: 65
  • Reputation: 257
  • Gender: Male
Re: chem 21 Discussion
« Reply #5 on: June 04, 2010, 12:20:24 pm »
u r rite sweetie
Logged

Offline leebux101

  • SF Geek
  • ****
  • Posts: 495
  • Reputation: 2966
Re: chem 21 Discussion
« Reply #6 on: June 04, 2010, 03:23:11 pm »
i wrote abt intermediate compounds and activation energy...
Logged
Pages: [1]   Go Up
« previous next »