d/dx [ln f(x)] = f '(x)/ f(x), where f ' (x) is the derivative of f(x).
Derivatives:
(a) ln(1-2x) > -2/ (1-2x)
(b) ln(a+bx) > b/ (a+bx)
(c) ln(x^2(x-1)) >>> clear this one, power is only 2 or 2(x-1)?
I think you forgot to add the brackets, must have been ln((x^2)(x-1)).
For this one, use the properties of logarithms. ln ((x^2)(x-1)) = ln (x^2) + ln (x-1)
Differentiate by step to get the derivative.
ln (x^2) > 2x/ (x^2)
ln (x-1) > 1/(x-1)
Therefore, ln (x^2) + ln (x-1) = 2x/ (x^2) + 1/(x-1)
Simplify further if you want.
(d) ln(2x) > 2/2x