New servers, hooraaaay! More bandwidth, more power.
hi! the mechanics ppr is tommorrow..Can anybody help me out with a question.It's from OCT/NOV 05 Q7)iii).How do u do it?
thanx but the answer is wrong for the last part,it's 3.456 J in the marking scheme.I think u made a mistake in calculating the distance for ball with mass 0.3gthe height at which A is above the floor is-->s=t(u+v)/2s=1.2(0+2.4)/2s=1.44mB's final velocity-->v^2=u^2+2asv^2=2*2*1.44=2.4 m/sdist travelled by B after string becomes slack until it comes to rest-->v^2=u^2+2as0=2.4^2+(2*-10*s)s=0.288mtherefore total dist=0.228+1.44=1.728mgain in gpe--> mgh=0.2*1.728*10=3.456 J