Qualification > Sciences
How to prepare for physics paper 1(cie)??????
Joseph_COOL:
thanks matabd :D
how about Q29 June 2008??
matabd:
Firstly:
x=Lambda X d / a
d = distance from double slits
a=slit spacing
since x(fringe SPacing) is directly proportional to lambda, as Lambda is Halved, so is x therefore your new x= 1.5mm. However, your slit spacing is doubled. SInce X is inversely proportional to slit spacing, since a is doubled, x must be halved , and so your new x=0.75mm. Just move in steps
halosh92:
--- Quote from: Joseph_COOL on May 18, 2010, 03:07:34 pm ---thanks very much halosh :D
--- End quote ---
ure welcome
Q29)
lambda= ax/D
700 * 10^-9 = [a * (3/1000) ]/D
( we divide 3 by 1000 to change it to m, and we multiply 100 by 10^-9 to change from nm to m)
D= [a * 0.003]/ (700 *10^-9)
this is D
now
labmda=ax/D
substitue that value of D in this formula
[350 * 10^-9 ] * ( a* 0.003)/(700 *10^-9) = 2ax
cancel out the "a" as its common on both sides
x= 0.00075 m *1000 = 0.75 mm
got it?
Joseph_COOL:
thanks very much guys got the whole thing :D :D
halosh92:
matabd could u plzz explain the pressure question again in a simplified way ;D
thx
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