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How to prepare for physics paper 1(cie)??????

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Friends:

--- Quote from: highly_ambitious on May 18, 2010, 02:40:08 pm ---lol...if we apply this logic then the difference in the height for two columns is still 'h' so P = rho.g.h  . according to which answer should be C !!

still don't know the right ans...somebody plzz help in this question.

--- End quote ---

A wild guess....
I think they might me talking about hieght of water in rhs above lhs
I know its the same thing but with different view...

Joseph_COOL:
Anyone plz explain answer for Q29 and Q28 in June 2008

halosh92:

--- Quote from: Joseph_COOL on May 18, 2010, 02:58:35 pm ---Plz June 2008 Q28 with explanation
Here is the attachment for the Question

--- End quote ---

whenever they say for eg : 600 lines per m
then d= 1/600
same thing here
the formula is
n lamda= dsin thita
n=3
d=1/N
3 lamda = 1/N sin thita
3 lamda N = sin thita
got it?

matabd:
Firstly for the Pressure One:

What i think is that Since the RHS new pressure is Patm.  - pgh and the LHS pressure is Patm+pgh. Thus the Increase is equal to RHS-LHS so you get 2pgh.


Also the Diffraction grating:

use dsintheta=nlambda

then u get sin Theta=3Lambda/d

they say that it has N lines per unit length. That means ur line spacing d = 1/N. Cos they said its N lines per Unit length, which can be said to be abt 1 metre. Putting that into the equation, sin Theta = 3LambaN

Joseph_COOL:
thanks very much halosh :D

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