Author Topic: m1 cie alevel...  (Read 978 times)

Offline ifraha18

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m1 cie alevel...
« on: May 17, 2010, 01:28:44 pm »
q3 june 2006..????y is dere no reaction force of table.???

Offline astarmathsandphysics

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Re: m1 cie alevel...
« Reply #1 on: May 17, 2010, 02:03:56 pm »
When i get home

Offline ifraha18

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Re: m1 cie alevel...
« Reply #2 on: May 17, 2010, 09:22:35 pm »
smbdi xplain.??plz

Offline astarmathsandphysics

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Re: m1 cie alevel...
« Reply #3 on: May 17, 2010, 09:33:33 pm »
The reacrion .isf the vertical component of F

Offline ifraha18

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Re: m1 cie alevel...
« Reply #4 on: May 17, 2010, 09:36:09 pm »
nrmli we would solv such prblem as fsin50 + r =12..but we dont tke R here.???y..????
fsin50 is vvrtical cmponent of f!!!wht about R.?the reaction ov tble.?

Offline astarmathsandphysics

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Re: m1 cie alevel...
« Reply #5 on: May 17, 2010, 09:53:14 pm »
Verically Fsin50=Fsin20+12
F(sin50-sin20)=12
F=12/(sin50-sin20)
G=Fcos50+Fcos 20

Offline ifraha18

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Re: m1 cie alevel...
« Reply #6 on: May 18, 2010, 12:25:02 am »
Thanks..but my qustion is dt y ddint we tke R the reaction force frm tble

Offline falafail

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Re: m1 cie alevel...
« Reply #7 on: May 18, 2010, 12:30:47 am »
Thanks..but my qustion is dt y ddint we tke R the reaction force frm tble

what reaction force??
12 N is not the weight of the particle, if you mean the normal contact force..?