i have these doubts too
june 2006 p1
Q33
Q24
Q25
Q28
Q24) since intensity is directly proportional to amplitude SQUARED then the sqaure root of intensity is proportional to amplitude, and therfore if the intensity is double then the intensity has to increase by a square root of 2, and the frequency is halfed therfore each wave takes double the number of squares, which means its B
Q25) the wavelength is equal to 340/500= 0.68
and it ask for the phase difference between two points on the SAME WAVE, and since the wavelength is 0.68, and the two points are 0.17 apart then its 0.17/0.68, then you have to multiply it by 360, this gives 90 degrees, and since pie is equal to 180 then the answer is B pie/2
Q28) we know that wavelength/distance between slits is = distance between two fringes/distance to screen
and therefore we want to know the relation between the distance between two fringes and the slit spacing therefore we have to re arrange the equation so that they are on different sides of the equation, but the equation already satisfies that and therefore, when the distance between the slits halfs the distance between 2 fringes has to double as they are inversely proportional because one is numerator and the other is denominator, and therefore that gives us a fringe spacing of 8, but then the distance to screen doubles, arranging the equation to make the distance to the screen on the left hand side we see that is directly proportional to the fringe spacing and therfore as it doubles the fringe spacing has to double to giving us 16mm