the parametric equations of a curve are:
x=3t^2+1 y=6t
(i) obtain an expression, in terms of t, for the gradient of the curve and find the equation of the normal to the curve at the point with parameter 1/2
(ii)find the coordinates of the points of intersection of the curve and the straight line whose parametric equations are :
x=T+5 y=2T-4
(b) the parametric equations of a curve are:
x=2cosz+ sinz, y=cosz - 2sinz
write down expressions for 2x+y and x-2y in terms of z, hence determine the cartesian equation of the curve in its simplest form.
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and to solve
2^x=3^x-2
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