1)
a) C2H4 (g) + H2 (g) --> C2H6 (g)
The enthalpy change of this reaction can be found by experiment to be -136 kJ/mol. Calculate the enthalpy change using the mean bond enthalpies given in book.
C-C = 347 / C-H = 413 / C=C = 612 / H-H = 436
now here's my answer to this
1 x (C=C) + 4 x (C-H) + 1 x (H-H) -> (612) + (4 x 413) + (436) = 2700
now for the products side -> 6 x (C-H) + 1 x (C-C) = 2825
2700 - 2825 = -125 kJ/mol ; exothermic reaction
so is that right? i just wanna doublecheck here
now for b)
The values will be different, why is this??
I was assuming it could be due to some experimental errors or heat loss ? is that right? either way what would your answer be?
Thank you! =)
Yeah, your method is correct and so is your calculation.
However, for the b part you are wrong. The data booklet quotes MEAN bond enthalpies. That is, they have found the average bond eenrgy for C-H bond.
Thus, the actual value of the C-H bond in ethene or ethane might be differ from the MEAN bond energy.
This why there is a difference.