Author Topic: Edexcel CHEMISTRY DOUBTS!!!!  (Read 246786 times)

elemis

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #855 on: April 07, 2011, 05:39:14 pm »
Show me some workings that you've done.

I want to see if you attempted this problem.

Offline Blizz_rb93

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #856 on: April 08, 2011, 02:51:45 pm »
Here's my work but idk if im right or no so i wanted to double check here

H2SO4 (l) + 2KCl (s) -> 2HCl (g) + K2SO4 (s)

Given that : H2SO4 (l) + 2KOH (s) -> K2SO4 (s) + 2H2O (l) ; enthalpy change = -342 kJ

and HCl (g) + KOH (s) -> KCl (s) + H2O (l) ; enthalpy change = -204 kJ

for the 2nd equation;
we put the products on the reactants side and the reactants on teh products sign
=> KCl (s) + H2O (l) -> HCl (g) + KOH (s)  and multiply each element by 2

=> 2KCl (s) + H2O (l) -> 2HCl (g) + 2KOH (s) ; so the enthalpy change right now is 204x2
the negative sign turns to positive as we reversed the equation


so the enthalpy change of reactoin wud be = -342 + (2x204) = 66kJ

i know that we wud have to multiply the 2nd reaction so that some parts of it wud be cancelled but im really confused=/ i just wanna know what are the STEPS we are required to know and how do we do these steps

Thank you

Offline Blizz_rb93

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #857 on: April 08, 2011, 03:40:19 pm »
Nevermind! :D I got it :D

Offline Blizz_rb93

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #858 on: April 08, 2011, 06:53:53 pm »
1)
a) C2H4 (g) + H2 (g) --> C2H6 (g)
The enthalpy change of this reaction can be found by experiment to be -136 kJ/mol. Calculate the enthalpy change using the mean bond enthalpies given in book.

C-C = 347 / C-H = 413 / C=C = 612 / H-H = 436

now here's my answer to this

1 x (C=C) + 4 x (C-H) + 1 x (H-H) -> (612) + (4 x 413) + (436) = 2700

now for the products side -> 6 x (C-H) + 1 x (C-C) = 2825

2700 - 2825 = -125 kJ/mol ; exothermic reaction

so is that right? i just wanna doublecheck here

now for b)
The values will be different, why is this??

I was assuming it could be due to some experimental errors or heat loss ? is that right? either way what would your answer be?


Thank you! =)

elemis

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #859 on: April 09, 2011, 08:55:20 am »
1)
a) C2H4 (g) + H2 (g) --> C2H6 (g)
The enthalpy change of this reaction can be found by experiment to be -136 kJ/mol. Calculate the enthalpy change using the mean bond enthalpies given in book.

C-C = 347 / C-H = 413 / C=C = 612 / H-H = 436

now here's my answer to this

1 x (C=C) + 4 x (C-H) + 1 x (H-H) -> (612) + (4 x 413) + (436) = 2700

now for the products side -> 6 x (C-H) + 1 x (C-C) = 2825

2700 - 2825 = -125 kJ/mol ; exothermic reaction

so is that right? i just wanna doublecheck here

now for b)
The values will be different, why is this??

I was assuming it could be due to some experimental errors or heat loss ? is that right? either way what would your answer be?


Thank you! =)

Yeah, your method is correct and so is your calculation.

However, for the b part you are wrong. The data booklet quotes MEAN bond enthalpies. That is, they have found the average bond eenrgy for C-H bond.

Thus, the actual value of the C-H bond in ethene or ethane might be differ from the MEAN bond energy.

This why there is a difference.

Offline Blizz_rb93

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #860 on: April 09, 2011, 09:45:41 am »
Thank you ! :D
+rep

Offline Blizz_rb93

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #861 on: April 10, 2011, 07:37:39 pm »
1. Name and write out the full structural formulae for the following compounds :
a) CH3(CH2)2Cl

b) CH3C(CH3)2CH(CH3)CH3

:S i really dont know how to write it down
when the (CH2)2 does that mean that theres two CH2 branches ??

and can someone show me the answers of both so i can double check my work?

Offline Shazizzzle

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #862 on: April 10, 2011, 10:02:00 pm »
1. Name and write out the full structural formulae for the following compounds :
a) CH3(CH2)2Cl

b) CH3C(CH3)2CH(CH3)CH3

:S i really dont know how to write it down
when the (CH2)2 does that mean that theres two CH2 branches ??

and can someone show me the answers of both so i can double check my work?
Yes, the (CH2)2 means there are two CH2.
See the image attached. I've written both the structural formula, as well as the displayed one, for better understanding.
•$#@2™•

Offline Blizz_rb93

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #863 on: April 11, 2011, 03:46:09 pm »
Yes, the (CH2)2 means there are two CH2.
See the image attached. I've written both the structural formula, as well as the displayed one, for better understanding.

Thank you =)

Offline Shazizzzle

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #864 on: April 11, 2011, 05:37:43 pm »
Where can I get the answers to the Examzone Unit 2 Test 1 for the Edexcel AS book?
I really need the answer to Q4 b) (iii) and (iv)on page 253 please, thanks. :)
•$#@2™•

Offline Aadeez || Zafar

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #865 on: April 11, 2011, 06:30:17 pm »
1. Name and write out the full structural formulae for the following compounds :
a) CH3(CH2)2Cl

b) CH3C(CH3)2CH(CH3)CH3

:S i really dont know how to write it down
when the (CH2)2 does that mean that theres two CH2 branches ??

and can someone show me the answers of both so i can double check my work?

(CH2) means R---CH2--CH2----R
FOR EXAMPLE : -CH3(CH2)5CHClCH3

WOULD MEAN

CH3----CH2----CH2----CH2----CH2----CH2--CHCl--CH3

naming - 2-chloro-octane



Yeh BaaabuRaao ka style hein!

Offline Aadeez || Zafar

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #866 on: April 11, 2011, 06:32:02 pm »
Thank you =)
if still any problem

then watch videos of khanadcademey.org (ORGANIC CHEMISTRY PLAYLIST)
u know it perfectly




Yeh BaaabuRaao ka style hein!

Offline EMO123

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #867 on: April 12, 2011, 08:32:13 am »
if still any problem

then watch videos of khanadcademey.org (ORGANIC CHEMISTRY PLAYLIST)
u know it perfectly


khan academy has got many more videos also so watch it all of chemistry also

Offline Blizz_rb93

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #868 on: April 12, 2011, 02:23:02 pm »
Explain why the different fractions of crude oil are collected at different temperatures?

Offline Master_Key

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #869 on: April 12, 2011, 02:25:41 pm »
Explain why the different fractions of crude oil are collected at different temperatures?

The chains of hydrocarbon are of different lengths so they have different boiling points and thus are separated at different temperatures.