I've been thinking about it for the past few minutes so I'll tell you what I came up with.
10 cm3 of NaOH reacted with 25 cm3 of the Weak acid ,so * if I subtract the 10 from the 25 then it'd be 15 cm3 remaining volume of weak acid.
*Why I subtracted it without feeling that I did something wrong is that in terms of concentration the ratio of the Weak acid to the Base is 1:1
so (15/1000 dm3) * (0.1 moldm-3) = 0.0015 moles
^ that could be a possibility , but not sure if it's right.
I hope I helped =]