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Author Topic: Edexcel PHYSICS Doubts  (Read 121380 times)

Offline Banana

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Re: Edexcel PHYSICS Doubts
« Reply #600 on: June 02, 2011, 04:42:26 pm »
Quote from: The Golden Girl on June 02, 2011, 04:38:49 pm
Usually when a lamp is brighter that's cuz of the Power it dissipates ;) that's why ,Which is why I suggest you write your answer according to the power equations if you don't get it ,let me know :)

thats because power relates to brightness....the greater the power, the brighter the lamp!  ;)
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Offline High-R

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Re: Edexcel PHYSICS Doubts
« Reply #601 on: June 02, 2011, 04:43:48 pm »
golden girl thankkks alot!!
;)


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Offline The Golden Girl =D

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Re: Edexcel PHYSICS Doubts
« Reply #602 on: June 02, 2011, 04:44:28 pm »
yup :)

Welcome :)
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Offline Malak

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Re: Edexcel PHYSICS Doubts
« Reply #603 on: June 02, 2011, 06:16:48 pm »
Oh god..Was is that simple  :o
I fail at this chapter..  :-[
Nywayz, thx you both :)

So whenever its about brightness I should talk about power? And the more power it dissipates the less brighter it is ? right ?  ???
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Re: Edexcel PHYSICS Doubts
« Reply #604 on: June 02, 2011, 06:37:16 pm »
Quote from: ang3l on June 02, 2011, 06:16:48 pm
Oh god..Was is that simple  :o
I fail at this chapter..  :-[
Nywayz, thx you both :)

So whenever its about brightness I should talk about power? And the more power it dissipates the less brighter it is ? right ?  ???

Nope , the more power it dissipates ,the brighter it is ;)
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Offline Banana

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Re: Edexcel PHYSICS Doubts
« Reply #605 on: June 02, 2011, 06:49:34 pm »
Quote from: ang3l on June 02, 2011, 06:16:48 pm
Oh god..Was is that simple  :o
I fail at this chapter..  :-[
Nywayz, thx you both :)

So whenever its about brightness I should talk about power? And the more power it dissipates the less brighter it is ? right ?  ???

Lol.....ur confused!! :o....study harder, this papers gonna be tough....*gut feeling*  :-[
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Offline The Golden Girl =D

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Re: Edexcel PHYSICS Doubts
« Reply #606 on: June 02, 2011, 06:51:16 pm »
Quote from: MujtabaM on June 02, 2011, 06:49:34 pm
Lol.....ur confused!! :o....study harder, this papers gonna be tough....*gut feeling*  :-[

Let's ALL Study harder ..who knows it might turn out to be easy ;)
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Offline Malak

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Re: Edexcel PHYSICS Doubts
« Reply #607 on: June 02, 2011, 07:14:43 pm »
Argh...I hate this chapter, Never got into my head  >:( (since IGz)

I Know M studying hard, M okay with waves and particle phy but this makes me go....  >:(

Ahh..I should go through it again  :-[

thx guys :)
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Re: Edexcel PHYSICS Doubts
« Reply #608 on: June 02, 2011, 07:28:26 pm »
welcome :)
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Offline Banana

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Re: Edexcel PHYSICS Doubts
« Reply #609 on: June 03, 2011, 04:21:33 am »
Quote from: The Golden Girl on June 02, 2011, 06:51:16 pm
Let's ALL Study harder ..who knows it might turn out to be easy ;)

Lol.....Inshallah it'll be alright!  ;)
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Offline The Golden Girl =D

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Re: Edexcel PHYSICS Doubts
« Reply #610 on: June 03, 2011, 08:36:59 am »
inshAllah :)
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Offline High-R

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Re: Edexcel PHYSICS Doubts
« Reply #611 on: June 03, 2011, 01:46:39 pm »
Inshaa Allah! :)

can any1 plz help me with 2011 phys unit6B (6PH08)
i dont get the Q2 part c ???
and even in Q2 part d how exactly do we do that?
all i know is u find the uncertainity by first finding the mean of the values given and then subtracting the mean from the lowest value(from the set of values given) thats how uncertainity is found right? so its +/- 0.2!!
and what do i do next? ???
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Offline High-R

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Re: Edexcel PHYSICS Doubts
« Reply #612 on: June 03, 2011, 01:55:10 pm »
confused in percentage uncertainity
percentage difference
uncertainity
etc
can u please tell how do u find ALL THESE?
:S
eg: in 2011 unit6b jan paper
Q3(ii) they ask percentage difference so (2.01-1.93)/ 1.97 = 4.1% is the working given in the markscheme, but why did we use 1.97(the mean value)? ???
« Last Edit: June 03, 2011, 01:58:00 pm by High-R »
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Offline Master_Key

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Re: Edexcel PHYSICS Doubts
« Reply #613 on: June 03, 2011, 02:03:41 pm »
Quote from: MujtabaM on June 02, 2011, 12:12:56 pm
Lol the 1st question is the 1st question of the specimen paper  :) See My Diagram Attached

Suppose the resistance of each resistor is 10 ohm......the total R through line 1 will be 10 ohm and the total R through line 2 will be 20 ohm......

So the current through line 2 will be halved( use the equation V=IR if R doubles, I is halved)

So using the Eq: P= I2 x R for line 2 if the current is halved, the P is quartered....D is the answer

lol....i know its tricky but go in sequence and use the right equatons  ;)

http://imageshack.us/photo/my-images/29/physicsl.jpg

From kirchoff's laws. Current is never used up. Current entering a circuit equals the current leaving it.

IN SERIES:-
Current is the same across all components and voltage is different across all components.

IN PARALLEL:-
Current is different across different components and voltage is same across all of them. ALL HOUSES AND INDUSTRIES ARE THUS CONNECTED IN PARALLEL TO THE NATIONAL GRID IN ORDER TO GET FULL P.D.
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Offline The Golden Girl =D

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Re: Edexcel PHYSICS Doubts
« Reply #614 on: June 03, 2011, 03:13:03 pm »
Paper Attached.

I've got loads of Qs  :-X

hmm can someone explain in section A Qs 4 ,5 , 6

Section B

Qs , 12]b) , 13]a)iii) , 17]b) , 19]a)ii)

Thanks in Advance :D
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