Edexcel PHYSICS Doubts

[dk bose]

Why do aircraft take off and land into the wind?
A ball on a snooker table is hit by another ball and travels at a distance of 50cm due west.it is then hit again and travels a distance of 30cm due north.Using a scale drawing,or by calculation,work out the snooker ball's displacement from its starting position.
A ship is travelling at 5m/s with a bearing of 20 deg east of north.there is a current of 1m/s flowing from the west.What is the resultant velocity of the ship?
Aristotle argued that a force was needed in order to keep an object moving.Describe some everyday situations that are consistent with this argument. Suggest a more scientific explanation for each case that you describe.

ANYONE PLZZZ TRY TO SOLVE THESE QUESTIONS AND GIVE THE SOLUTIONS AS FAST AS POSSSIBLE!!!!!! ITZZZZ URGENT!!!!!!!!

[astarmathsandphysics]

aircraft take off into the wind to increase lift at low speeds. Lif depends on the speed of air over the wings.
For the second question you have to draw a scale diagram for which you need an artist.
3rd question - pushing a car uphill.
See here http://www.astarmathsandphysics.com/ib_physics_notes/history_and_development_of_physics/ib_physics_notes_aristotles_idea_of_motion.html
The scientific view would be that air resistance acts against the direction of motion to slow the velocity.

[EVIL DOCTOR]

Your dog is running around the grass in your back
yard. He undergoes successive displacements 3.50 m south,
8.20 m northeast, and 15.0 m west. What is the resultant
displacement?

need asap

[Malak]

Your dog is running around the grass in your back
yard. He undergoes successive displacements 3.50 m south,
8.20 m northeast, and 15.0 m west. What is the resultant
displacement?

need asap

Draw a diagram like this (attached)

You have to resolve the pink vector into its component.
As it is in the north-east direction the angle would be 45.
So the x-component will be 8.2cos45 and y will be 8.2sin45

Now add them up as we normally do in vectors.

[astarmathsandphysics]

In north direction -3.5 +8.2 cos 45=2.3
east 8.2 sin 45 -15 =-9.2
displacement= 2.3 m north and -9.2 east

[Romeesa-Chan]

dear in physics unit 1, i came across the spec. point, that is ==

demonstrate an understanding of how ICT can be used to collect data for, and display, displacement/time  and velocity/time graphs for uniformly accelerated motion and compare this with traditional methods in terms of reliability and validity of data///

wat does this spec, point want and expect to know from us??? can u give me excellent notes for this.. Wat does ICT stand for???

Motions can be represented using graphs.
Traditionally, data were collected using rulers and stopwatches.
ICT methods are more accurate, efficient and fast.
An example of ICT method is a motion sensor.

[EVIL DOCTOR]

Draw a diagram like this (attached)

You have to resolve the pink vector into its component.
As it is in the north-east direction the angle would be 45.
So the x-component will be 8.2cos45 and y will be 8.2sin45

Now add them up as we normally do in vectors.

the question didnot mention the angle of north east
who told u its 45 degree ??

[astarmathsandphysics]

nort east is half way between north and east
north=0
east =90
(0+90)/2=45

[EVIL DOCTOR]

particle initially located at the origin has an acceleration
of aS
5 3.00j^ m/s2 and an initial velocity of vS
i 5 5.00i^ m/s.
Find (a) the vector position of the particle at any time t,
(b) the velocity of the particle at any time t, (c) the coordinates
of the particle at t 5 2.00 s, and (d) the speed of the
particle at t 5 2.00 s.

[astarmathsandphysics]

is difficult to read your question Evil Doctor. Can you make it clearer?

[EVIL DOCTOR]

particle initially located at the origin has an acceleration
of a
= 3.00j^ m/s2 and an initial velocity of v is
 = 5.00i^ m/s.
Find (a) the vector position of the particle at any time t,
(b) the velocity of the particle at any time t, (c) the coordinates
of the particle at t = 2.00 s, and (d) the speed of the
particle at t= 2.00 s.

[astarmathsandphysics]

a)s=ut+1/2at^2=5it+1.5jt^2
b)v=u+at=5i+3jt
c)s=5i*2+1.5j*2^2=10i+6j
d)v=5i+3j*2=5i+6j so speed =sqrt(5^2+6^2)=7.81m/s

[dk bose]

A bullet of mass 50g is fired horizontally and embeds itself into a stationary
block of wood of mass 1.25 kg. Calculate the speed of the bullet if the
block moves forward with a speed of 3.9m/s after the impact.

plzz solve this question and give the solutions as fast as possible!!!!

[astarmathsandphysics]

conservation of momentum.
to start, momentum is due to bullet only:m*v=0.05*v
after, momentum is due to bullet + block together m*v=(1.25+0.05)*3.9=5.07
momentum before=momentum after
0.05*v=5.07 so v=5.07/0.05=101.4 m/s

[dk bose]

Two cars collide at an intersection between two roads. One car has a mass of 900kg and is travelling at due North at 25m/s , and the other car has a mass of 750 kg and is travelling due East at 35 m/s ,
The cars remain together after the collision. Calculate the velocity of the cars immediately after the collision, and the fraction of kinetic energy lost. Account for the loss of kinetic energy.

solve this question.its urgent!!!!