Author Topic: phys pap 1  (Read 785 times)

Offline winnie101

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phys pap 1
« on: May 07, 2010, 03:43:27 pm »
could someone plz explain to me ques. 5,7,15,18,20,and 29 form m/j 2009 paper 1 physics cie AS level
Thanks

Offline beacon_of_light

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Re: phys pap 1
« Reply #1 on: May 08, 2010, 10:50:01 am »
the answer for q5 is D..as v know that in the second part of the ball's journey it travels with constant velocity..the displacment time graph is a straight line graph...this condition is satisfied by D only...


Offline tmisterr

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Re: phys pap 1
« Reply #2 on: May 08, 2010, 04:56:01 pm »
7 A. second law is F=ma so is force is 0 then a is 0 therefore if an object is at rest it will remain at rest, and it is moving at a constant speed it will remain moving at a constant speed which is the first law

15 it's height decreases by h/2 and its mass also decreases by m/2 so P.E loss is m/2*h/2*g=mgh/4 which is B

18 initially height are the same, pressure is the same at both sides at it is equal to atmospheric pressure. an change in pressure will be due to change in pressure of the gas. So one side decreases by h and the other side increases by h also. so the total change in height is 2h. pressure increase in the flask is there 2hpg D

20 since they are the same materials, they have the same young modulus and since they are being strectched to the same extension, you need to use 1/4 the force you use on P to get the same extension in q so 1/0.25= 4

29 D. when it enter the magnetic field, it experiences a force of Ee. this force is acting in the opposite direction to the velocity so the electron is decelerating. using linear motion equation, v2=u2-2as, where a is F/m that is Ee/m and u is v, and s is x, making x the subject you get mv2/2Ee

Offline winnie101

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Re: phys pap 1
« Reply #3 on: May 09, 2010, 07:15:39 pm »
Thanks u guys so much