Author Topic: S1 and S2 DOUBTS HERE!!!!  (Read 63267 times)

Offline khi2ruh

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Re: S1 DOUBTS HERE!!!!
« Reply #60 on: May 26, 2010, 01:29:14 am »
hey im stuck!!

n09 Q5 (a) (i) (ii) and b (ii)

Offline Saladin

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Re: S1 DOUBTS HERE!!!!
« Reply #61 on: May 26, 2010, 08:11:46 am »
hey im stuck!!

n09 Q5 (a) (i) (ii) and b (ii)

Sorry m8, I do Edexcel.

Offline Sweet_03

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Re: S1 DOUBTS HERE!!!!
« Reply #62 on: May 26, 2010, 09:17:33 am »
Hello , can someone plz help

June2005
Q7 (d)

P( sci | RH ) = P(sci 'n' RH) / P(RH) = (24÷110)/ (110÷148)
thats wat i did , but obviously its wrong
how do you find P(sci 'n' RH) ???
« Last Edit: May 26, 2010, 09:19:20 am by Sweet_03 »

Offline Saladin

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Re: S1 DOUBTS HERE!!!!
« Reply #63 on: May 26, 2010, 10:07:12 am »
Hello , can someone plz help

June2005
Q7 (d)

P( sci | RH ) = P(sci 'n' RH) / P(RH) = (24÷110)/ (110÷148)
thats wat i did , but obviously its wrong
how do you find P(sci 'n' RH) ???

On it now, will be finished soon iA.

Offline Saladin

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Re: S1 DOUBTS HERE!!!!
« Reply #64 on: May 26, 2010, 10:39:15 am »
Hello , can someone plz help

June2005
Q7 (d)

P( sci | RH ) = P(sci 'n' RH) / P(RH) = (24÷110)/ (110÷148)
thats wat i did , but obviously its wrong
how do you find P(sci 'n' RH) ???

This is how you do it.

(c)You have to find the number of people that are right handed.

\frac{80}{100}*30+\frac{75}{100}*68+\frac{70}{100}*50=110

So, there are a total of 110 right handers, and a total of 148 students.

So, \frac{110}{148}=0.743

(d) This is basically asking, out of 110 right handers, what is the probability that it will be a science student?

So, the number of science students that are right handed, are \frac{80}{100}*30=24

Now, \frac{24}{110}=0.218

Offline Sweet_03

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Re: S1 DOUBTS HERE!!!!
« Reply #65 on: May 26, 2010, 02:08:47 pm »
Oh! i was trying to use the formula
okay now it makes sense =')
thank you

Offline Saladin

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Re: S1 DOUBTS HERE!!!!
« Reply #66 on: May 26, 2010, 02:23:01 pm »
Oh! i was trying to use the formula
okay now it makes sense =')
thank you

Sometimes, you need to understand the whole concept, and understand the feel of the question before attempting it.

Offline immortal

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Re: S1 DOUBTS HERE!!!!
« Reply #67 on: May 26, 2010, 02:33:40 pm »
Sometimes, you need to understand the whole concept, and understand the feel of the question before attempting it.
this also saves a lot of time..
Life is short...so live it to da fullest :)

Offline Saladin

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Re: S1 DOUBTS HERE!!!!
« Reply #68 on: May 26, 2010, 02:42:07 pm »
this also saves a lot of time..

Just doin ma job.  8)

Offline Summer :]

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Re: S1 DOUBTS HERE!!!!
« Reply #69 on: May 26, 2010, 02:54:36 pm »
Find
E( x^2 + 4X - 3)
E(x) = 2.6
and the answer = 15.6
how did they get it ?????

Offline astarmathsandphysics

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Re: S1 DOUBTS HERE!!!!
« Reply #70 on: May 26, 2010, 02:59:23 pm »
Find
E( x^2 + 4X - 3)
E(x) = 2.6
and the answer = 15.6
how did they get it ??
You must know the variance to answer this question. What is it?

Offline coatseville

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Re: S1 DOUBTS HERE!!!!
« Reply #71 on: May 26, 2010, 03:06:55 pm »
I have two questions...
From the January 2009 paper
question 3e) could you please explain fully how to do this..
and for 2b) why must we use the addition rule? When we didnt in 2a)
Thankyou SO much :)

Offline Summer :]

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Re: S1 DOUBTS HERE!!!!
« Reply #72 on: May 26, 2010, 03:20:52 pm »
Find
E( x^2 + 4X - 3)
E(x) = 2.6
and the answer = 15.6
how did they get it ??
You must know the variance to answer this question. What is it?

Var 1.44

Offline astarmathsandphysics

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Re: S1 DOUBTS HERE!!!!
« Reply #73 on: May 26, 2010, 03:37:37 pm »
Find
E( x^2 + 4X - 3)
E(x) = 2.6
and the answer = 15.6
how did they get it ??
You must know the variance to answer this question. What is it?

Var 1.44
V(X0=E(X^2)-(E(X))^2
1.44=E(X^2)-2.6^2
E(X^2)=1.44+6.76=8.18
E( x^2 + 4X - 3)=E(X^2)-4E(X)-3=8.18-4*2.6-3=8.18-1.4=-5.22

Offline Blizz_rb93

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Re: S1 DOUBTS HERE!!!!
« Reply #74 on: May 26, 2010, 03:53:28 pm »
June 2001
Question 1 a)
they said to find the mean and the standard deviation for the data given
in the markscheme they gave something different to what i solved
the mean i knew how to do but the standard deviation was the weird part

My solution : Standard Deviation = Square root of [(sum of x^2 divided by n)-(mean)^2]
my answer gives me Math Error

and in the markscheme the answer comes out 4 :/
plz someone help asap
thank you