Qualification > Math

S1 and S2 DOUBTS HERE!!!!

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Ivo:

--- Quote from: Deadly_king on November 11, 2010, 05:16:55 am ---Nope........you did it wrong there dude.

The question asked at least a six form both dices but exactly one six should be obtained.

Hence probable results are :
1. 6 from biased die and any other number from unbiased die.
2. Any other number from unbiased die and 6 from unbiased die.

Probability : (1/4 x 5/6) + (3/4 x 1/6) = 1/3

--- End quote ---

Hmm, apparently the answer is 8/9.  Any ideas?

astarmathsandphysics:
got 8/9. faffing around with scanner

astarmathsandphysics:
here

Arthur Bon Zavi:
Instinct change ! No doubts here now, for anybody. :o

vondutchLG:
A:one of the two dice shows a 6
B:at least one of them shows a 6

first find B
a tree diagram would help...........
1/4*1/6+1/4*5/6+3/4*1/6=3/8
P(B)=3/8
P(A)=1/4*5/6+3/4*1/6=1/3
P(A!B)=this means probabiltiy of A given that B
P(A)=1/3 / 3/8=8/9

hop u get it

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