Qualification > Math

S1 and S2 DOUBTS HERE!!!!

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Freaked12:
Oh

This is already done
sorry

Ivo:
A dice is known to be biased in such a way that, when it is thrown, the probability of a 6 showing is .  This biased dice and an ordinary fair dice are thrown.  Find the probability that exactly one of the two dice shows a 6, given that at least one of them shows a 6.

Many thanks in advance; what does that last sentence even mean?!

Arthur Bon Zavi:

--- Quote from: Ivo on November 10, 2010, 08:02:59 pm ---A dice is known to be biased in such a way that, when it is thrown, the probability of a 6 showing is .  This biased dice and an ordinary fair dice are thrown.  Find the probability that exactly one of the two dice shows a 6, given that at least one of them shows a 6.

Many thanks in advance; what does that last sentence even mean?!

--- End quote ---

You have to find the probability that; if together both the dices are thrown, at-least from both, 1 shows a six, and from both 1 has to show 6.

1       1         5
-- + ---   = -----
4       6         12

Is this the answer ?

Deadly_king:

--- Quote from: Ancestor on November 11, 2010, 05:03:55 am ---You have to find the probability that; if together both the dices are thrown, at-least from both, 1 shows a six, and from both 1 has to show 6.

1       1         5
-- + ---   = -----
4       6         12

Is this the answer ?

--- End quote ---

Nope........you did it wrong there dude.

The question asked at least a six form both dices but exactly one six should be obtained.

Hence probable results are :
1. 6 from biased die and any other number from unbiased die.
2. Any other number from unbiased die and 6 from unbiased die.

Probability : (1/4 x 5/6) + (3/4 x 1/6) = 1/3

Arthur Bon Zavi:

--- Quote from: Deadly_king on November 11, 2010, 05:16:55 am ---Nope........you did it wrong there dude.

The question asked at least a six form both dices but exactly one six should be obtained.

Hence probable results are :
1. 6 from biased die and any other number from unbiased die.
2. Any other number from unbiased die and 6 from unbiased die.

Probability : (1/4 x 5/6) + (3/4 x 1/6) = 1/3

--- End quote ---

Yeah !! :D

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