Author Topic: All Mechanics DOUBTS HERE!!!  (Read 85139 times)

Offline thecandydoll

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Re: All Mechanics DOUBTS HERE!!!
« Reply #330 on: October 17, 2010, 09:10:11 am »
I just realised thats the frictional force!
TTHANKK YOU
scratch that

Offline Ghost Of Highbury

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Re: All Mechanics DOUBTS HERE!!!
« Reply #331 on: October 19, 2010, 09:46:16 am »
winter 2009, paper 41..

Q4..

(AS level)

Could someone plz include diagrams and explanations in the answer...thanks a lot..
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Offline Deadly_king

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Re: All Mechanics DOUBTS HERE!!!
« Reply #332 on: October 19, 2010, 10:37:41 am »
winter 2009, paper 41..

Q4..

(AS level)

Could someone plz include diagrams and explanations in the answer...thanks a lot..

i) First you need to resolve vertically so as to find the reaction.
R = 80 x cos 20 = 75.2 N

Since the block is at rest ----> a = 0
Using Newton's second law of motion : F = ma
T + Fr - mgsin x = ma
where T : tension in the string,
Fr : frictional from between block and the inclined plane
mgsin x : component of weight down the plane and x being the angle of inclination of the plane

Given T =13 and a=0 ----> 13 + Fr - 80sin 20 = 0
Hence Fr is found to be 14.4 N

ii) String is cut off but block is still at rest ----> Fr = mgsin x

Fr = uR where u is the coefficient of friction between block and plane

Hence 80sin 20 = u(75.2) -----> u = 0.364

Sorry I could not add a diagram :-[

Hope it helps :)
« Last Edit: October 19, 2010, 10:39:51 am by Deadly_king »

Offline Ghost Of Highbury

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Re: All Mechanics DOUBTS HERE!!!
« Reply #333 on: October 19, 2010, 11:21:50 am »
i) First you need to resolve vertically so as to find the reaction.
R = 80 x cos 20 = 75.2 N

Since the block is at rest ----> a = 0
Using Newton's second law of motion : F = ma
T + Fr - mgsin x = ma
where T : tension in the string,
Fr : frictional from between block and the inclined plane
mgsin x : component of weight down the plane and x being the angle of inclination of the plane

Given T =13 and a=0 ----> 13 + Fr - 80sin 20 = 0
Hence Fr is found to be 14.4 N

ii) String is cut off but block is still at rest ----> Fr = mgsin x

Fr = uR where u is the coefficient of friction between block and plane

Hence 80sin 20 = u(75.2) -----> u = 0.364

Sorry I could not add a diagram :-[

Hope it helps :)

erm, is that question 4 of winter 2009 M1 (paper 41) paper? :-/
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Re: All Mechanics DOUBTS HERE!!!
« Reply #334 on: October 19, 2010, 01:36:35 pm »
Hey ,I just wanted to know How Am i supposed to study for M1 , I want to know what is the best way to study for this Subject ?

Because i got this really Low grade in the Quiz and I don't want to show my Dad :S  Since I'm dead meat for sure  :-X :-X

Thank You In Advance .
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Re: All Mechanics DOUBTS HERE!!!
« Reply #335 on: October 19, 2010, 02:42:48 pm »
@GG are you doing Edexcel or CIE M1 ?

Offline SpongeBob

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Re: All Mechanics DOUBTS HERE!!!
« Reply #336 on: October 19, 2010, 03:19:01 pm »
winter 2009, paper 41..

Q4..

(AS level)

Could someone plz include diagrams and explanations in the answer...thanks a lot..

I hope you understood the post above :/

Nov 09 Q4 --> https://studentforums.biz/math-146/mechanics-question/15/




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Offline Deadly_king

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Re: All Mechanics DOUBTS HERE!!!
« Reply #337 on: October 19, 2010, 04:14:48 pm »
erm, is that question 4 of winter 2009 M1 (paper 41) paper? :-/

That was June 09 p4 No4


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Re: All Mechanics DOUBTS HERE!!!
« Reply #338 on: October 19, 2010, 04:39:14 pm »
@GG are you doing Edexcel or CIE M1 ?

Edexcel
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Re: All Mechanics DOUBTS HERE!!!
« Reply #339 on: October 19, 2010, 05:29:53 pm »
Hey ,I just wanted to know How Am i supposed to study for M1 , I want to know what is the best way to study for this Subject ?

Because i got this really Low grade in the Quiz and I don't want to show my Dad :S  Since I'm dead meat for sure  :-X :-X

Thank You In Advance .

M1 is supposed to be easy especially for those doing physics.

Hmm............studying M1 does not actually require much knowledge. You just need to understand the basic principles. Then only practice might help you perform well ;)

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Re: All Mechanics DOUBTS HERE!!!
« Reply #340 on: October 19, 2010, 07:36:05 pm »
M1 is supposed to be easy especially for those doing physics.

Hmm............studying M1 does not actually require much knowledge. You just need to understand the basic principles. Then only practice might help you perform well ;)

Practice ..Ohh Ya :S :S

Thanks  :)
Verily, in the remembrance of Allah do hearts find rest(13:28)

Please, Don't forget to Include GG in your Prayers =D

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Re: All Mechanics DOUBTS HERE!!!
« Reply #341 on: November 26, 2010, 04:09:31 pm »
Mechanics shall drive me nuts soon!! :/

Question, from the chapter vectors, I came across this question and I got the answer from the CD that came with the book, but I can't understand

Q. An aeroplane flies from airport A to airport B 80 km away on a bearing of 070?. From B the aeroplane flies to airport C, 60 km from B. Airport C is 90 km from A. Find the two possible directions for the course set by the aeroplane on the second stage of its journey.

Ans. ?cos?? =(62+82?92) / (2×6×8) =0.19791…
? =78.6°(3 s.f.)

?bearing ofC from B is
180°+70°??=171.4°(1 d.p.) or 180°+70°+?=323.6°(1 d.p.)

& the diagram that they showed is attached below.

I don't understand how did they reach to this diagram and hence the solution!

Any help will be much appreciated!

Thanks a lot in advance! :)

Offline ashish

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Re: All Mechanics DOUBTS HERE!!!
« Reply #342 on: November 27, 2010, 06:41:24 am »
Mechanics shall drive me nuts soon!! :/

Question, from the chapter vectors, I came across this question and I got the answer from the CD that came with the book, but I can't understand

Q. An aeroplane flies from airport A to airport B 80 km away on a bearing of 070?. From B the aeroplane flies to airport C, 60 km from B. Airport C is 90 km from A. Find the two possible directions for the course set by the aeroplane on the second stage of its journey.

Ans. ?cos?? =(62+82?92) / (2×6×8) =0.19791…
? =78.6°(3 s.f.)

?bearing ofC from B is
180°+70°??=171.4°(1 d.p.) or 180°+70°+?=323.6°(1 d.p.)

& the diagram that they showed is attached below.

I don't understand how did they reach to this diagram and hence the solution!

Any help will be much appreciated!

Thanks a lot in advance! :)


it's like or it's a locus question.
locus of a point of r cm is a circle with radius r cm
 and in this particular question C will be where the two circle intersect each other

sorry for the handwriting
« Last Edit: November 27, 2010, 06:46:14 am by ashish »

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Re: All Mechanics DOUBTS HERE!!!
« Reply #343 on: November 27, 2010, 07:44:40 am »
it's like or it's a locus question.
locus of a point of r cm is a circle with radius r cm
 and in this particular question C will be where the two circle intersect each other

sorry for the handwriting

Ohhh, now that makes sense!

Thanks a lot!  ;D

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Re: All Mechanics DOUBTS HERE!!!
« Reply #344 on: November 27, 2010, 12:18:15 pm »
One more question!

A particle P is moving along the x-axis with constant deceleration 2.5ms?2. At time t=0s, P passes through the origin with velocity 20ms?1 in the direction of x increasing. At time t=12s, P is at the point A. Find

(a) the distance OA,

(b) the total distance P travels in 12 s.


The answer for (a) is 60m and for (b) it's 100m.

HOW?