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All Mechanics DOUBTS HERE!!!

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astarmathsandphysics:
They resolved vertically. The answer is a the same

melony:
help please, how do u determine the direction of the resultant of three coplanar forces. i.e mechanics paper 04/m/j/05
 ???
thank yu!  :)

nid404:
I assume it's the second question

check the diagram

A=7+3.2=10.2
B=3.83N
C=5.2N
D= 3N

Resolving these

A-C=5N
B-D=0.83N

Now find the resultant

R2=

R=5.09N

tan = 0.83/5
=9.43o anticlockwise from force of 7N

melony:
wow!! ofcourse!! thanks soo much nid!!.. +rp!
 ;)

Fenomenoe9:
Can any1 help in this question... please.

Its in June 2008 M1 paper question 5.

Two forces P and Q act on a particle at a point O. The force P has magnitude 15 N and
the force Q has magnitude X newtons. The angle between P and Q is 150°, as shown in
Figure 1. The resultant of P and Q is R.

Given that the angle between R and Q is 50°, find
(a) the magnitude of R,   (4)
(b) the value of X.    (5)

the diagram is something like this its in the question :

                     P
                        \
                         \  
                          \
                           \
                            \._________________ Q
                          O
angles is 150 ^^

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