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All Mechanics DOUBTS HERE!!!

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Saladin:

--- Quote from: damlaj on May 10, 2010, 10:11:24 am ---2007 january paper question 7 last part

and thanks

--- End quote ---

I am quite sure its Edexcel.




We need to find out the final velocity that the particle reaches after the other particle has fallen.




Now we need to find the time it takes for it to stop, as the resultant force is not towards going down. Thus we have to find the acceleration.





Using this, calculate the time taken for the particle to come to rest.








The time taken to go up, is the time taken to go down, as there is same acceleration.
Thus the total time taken is
Thus the total time taken is 0.51 seconds,

Uchia:
lol yeah thnxs i used to solve it in the same way but the last step i am always confused about cz some old questions you didn't need to multiply by 2 but this question here required to do so y??

Saladin:

--- Quote from: damlaj on May 10, 2010, 11:46:08 am ---lol yeah thnxs i used to solve it in the same way but the last step i am always confused about cz some old questions you didn't need to multiply by 2 but this question here required to do so y??

--- End quote ---

Because it said that how long it takes for it to be taught again. That means up and down.

Phosu:
jun 02 ques 4a
i just straight off rote R=6gCos30+PSin30
but marking scheme has some other calculations, can someone plz explain how to get that.

nid404:
must be edexcel...i don't have the paper

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