Author Topic: All Mechanics DOUBTS HERE!!!  (Read 88428 times)

**RoRo**

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Re: All Mechanics DOUBTS HERE!!!
« Reply #405 on: March 21, 2011, 11:57:36 am »
look at the arrows on the 8N force on the diagram below. The force is pushing the block into the plane

Oh, okay, I got it, thanks a lot! :)

Offline The Golden Girl =D

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Re: All Mechanics DOUBTS HERE!!!
« Reply #406 on: March 22, 2011, 04:03:54 pm »
Chapter 6 , Page 146 , Q1}a] ..... Q2}a] ....and Q4}a]

I NEED this URGENTLY :'(

Verily, in the remembrance of Allah do hearts find rest(13:28)

Please, Don't forget to Include GG in your Prayers =D

elemis

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Re: All Mechanics DOUBTS HERE!!!
« Reply #407 on: March 22, 2011, 04:05:54 pm »
Chapter 6 , Page 146 , Q1}a] ..... Q2}a] ....and Q4}a]

I NEED this URGENTLY :'(



10 minutes.

elemis

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Re: All Mechanics DOUBTS HERE!!!
« Reply #408 on: March 22, 2011, 04:10:45 pm »
Position vector after a time = Initial Position vector + velocity*time

Hence,
Q1
r = 3j +8i
  = 8i +3j

Q2
6i+13j = 2i+3j + 2v

4i +10j = 2v

2i +5j= v

Can you apply the same method for Question 4 ?

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Re: All Mechanics DOUBTS HERE!!!
« Reply #409 on: March 22, 2011, 04:14:21 pm »
Position vector after a time = Initial Position vector + velocity*time

Hence,
Q1
r = 3j +8i
  = 8i +3j

Q2
6i+13j = 2i+3j + 2v

4i +10j = 2v

2i +5j= v

Can you apply the same method for Question 4 ?

Thanks mate :)
« Last Edit: March 22, 2011, 04:27:08 pm by ~ The Golden Girl ~ »
Verily, in the remembrance of Allah do hearts find rest(13:28)

Please, Don't forget to Include GG in your Prayers =D

**RoRo**

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Re: All Mechanics DOUBTS HERE!!!
« Reply #410 on: April 07, 2011, 07:25:36 pm »
I've got a long list of doubts this time!  ;D

Check the attachment for the questions and the answers [at the bottom]

I need the steps for the following questions:

4b)
5a)b)
7c)d)
8c)

Thanks A LOT in advance! :)

Offline iluvme

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Re: All Mechanics DOUBTS HERE!!!
« Reply #411 on: April 07, 2011, 08:15:56 pm »
4 b)

Not sure about the others :S
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**RoRo**

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Re: All Mechanics DOUBTS HERE!!!
« Reply #412 on: April 07, 2011, 08:32:56 pm »
4 b)

Not sure about the others :S

Thank you so much!

I did a super-stupid mistake, instead of adding 4 to 3 and writing the answer as 7, I wrote it as 1! -.-"

Offline Darkstar3000

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Re: All Mechanics DOUBTS HERE!!!
« Reply #413 on: April 09, 2011, 03:53:29 pm »
Question 5 Jan 2008 : http://www.carlgauss.co.uk/PDFs/A-Level%20Papers/M2/M2%20-%202008%20Jan%20Paper.pdf

Mark scheme : http://www.carlgauss.co.uk/PDFs/A-Level%20Papers/M2/M2%20-%202008%20Jan%20Mark%20Scheme.pdf





Am I wrong or is the mark scheme wrong because when I calculate the answer I'm getting 0.72 but they get 0.18

----------------------------------------------------------

How do I do question number 6, the whole thing ?

Thanks

elemis

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Re: All Mechanics DOUBTS HERE!!!
« Reply #414 on: April 09, 2011, 07:10:41 pm »
I will answer this tomorrow morning.

elemis

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Re: All Mechanics DOUBTS HERE!!!
« Reply #415 on: April 10, 2011, 06:20:02 am »
Question 5

Considering vertical forces you will find that R = 4mg

Taking moments about point B :

2a*cos60*mg + 3a*cos60*3mg + 4a*cos30*4mg\mu = 4a*cos60*4mg

Solve this and you will get an answer of : 0.180

Question 6

Attempt the question and show me your workings. I'll see where you've gone wrong and correct you.

Offline Darkstar3000

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Re: All Mechanics DOUBTS HERE!!!
« Reply #416 on: April 10, 2011, 11:59:08 am »
Question 5

Considering vertical forces you will find that R = 4mg

Taking moments about point B :

2a*cos60*mg + 3a*cos60*3mg + 4a*cos30*4mg\mu = 4a*cos60*4mg

Solve this and you will get an answer of : 0.180

Question 6

Attempt the question and show me your workings. I'll see where you've gone wrong and correct you.

Thank you for question 5.

As for 6, I have no idea where to start it

Offline jellybeans

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Re: All Mechanics DOUBTS HERE!!!
« Reply #417 on: April 11, 2011, 08:01:44 am »
Question on the motion of a projectile on an inclined plane

For (a) I equated j component = 0
-> (UsinthetaT - ½gcosthetaT2) = 0
-> (Usin60T - ½gcos30T2) = 0
-> T=0, (root3)U/2 - (root3)g/4(T))T=0
-> (root3)g/4(T) = (root3)U/2
so i got -> T=2U/g

but it says 2U/g(root3)

could somebody help me on this question please.. thanks! :)
« Last Edit: April 11, 2011, 08:15:52 am by jellybeans »
You said I must eat so many lemons cause I am so bitter.

**RoRo**

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Re: All Mechanics DOUBTS HERE!!!
« Reply #418 on: April 12, 2011, 12:40:02 pm »
Can anyone please solve for me Question 1 in January 2006 and Question 8d in June 2005 [Edexcel Papers] with explanation?

Thank you! :)

Offline HUSH1994

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Re: All Mechanics DOUBTS HERE!!!
« Reply #419 on: April 17, 2011, 12:55:21 pm »
MJ 2003 Q4 part 2,i did it wrong and then the mark scheme had 2 dots above x,anyone can help me with this