guys 6(iv) in June 09 on the paper attached here , shouldnt it be 0.72m? cuz in the mark scheme its slightly larger than that ? Plz explain , thank u
no, the markscheme's right
after A hits the floor, B keeps moving upwards with a= -10 and u=1.2
to calculate the maximum height reached, you use v=0
so you get s=0.072 AFTER A HITS THE FLOOR
that means that B is already 0.36 + 0.36 m above the ground.
so 0.36 + 0.36 + 0.072 = 0.792 m.
woops, i didn't notice astar's post. oh well, at least i got practice i guess