C1 and C2 DOUBTS HERE!!!!!

[The Golden Girl =D]

Plug in values for x, start methodically from zero until you get a number. In this case I got x=1 as a solution.

Hence, (x-1) is a solution.

Perform algebraic division of the original equation with (x-1) and find the resultant quadratic equation.

Factorise the quadratic.

State the solutions.

Part in bold : you mean I try random numbers until I get the answer as Zero , right ?

[elemis]

Part in bold : you mean I try random numbers until I get the answer as Zero , right ?

Yes.

[narnia]

Q1)Find the possible values of x for which 2^2x+1=3(2^x)-1

i need an explanation...all the steps =S

Q2)Given that p=log_q16, express in terms of p;
       log_q(8q)

[narnia]

can someone pleasee answer 

[elemis]

can someone pleasee answer 

5 minutes.

[elemis]

Q1)Find the possible values of x for which 2^2x+1=3(2^x)-1

i need an explanation...all the steps =S

Q2)Given that p=log_q16, express in terms of p;
       log_q(8q)

1) Your equation can be re-written as : (2^x)²*2 = 3(2^x)-1

Let y = 2^x

Hence, 2y² -3y +1=0

Solve this quadratic. You will find the value of 2^x. Use logs to find the value of x.

[elemis]

Q1)Find the possible values of x for which 2^2x+1=3(2^x)-1

i need an explanation...all the steps =S

Q2)Given that p=log_q16, express in terms of p;
       log_q(8q)

2)  log_q(8q)

By the law of logs :



and using the power rule :



Hence,

4/3 p +1

[narnia]

2)  log_q(8q)

By the law of logs :



and using the power rule :



Hence,

0.75p +1

where did the pwr 3/4 come from?

[elemis]

where did the pwr 3/4 come from?

I made a small typo. I edited my post.

16^4/3  = 8

[narnia]

I made a small typo. I edited my post.

16^4/3  = 8

yea got it now...
Thanks a lot

[narnia]

Solve the inequality x² - 5x - 14>0,   I get (x+2)>0 & (x-7)>0, then what??? Textbk ans says x<-2, isn't it supposed to be x>-2?? The other ans of mine matches tho, x>7.

[iluvme]

You could try either ways, Graphical or tabular.

Hope you got it

[narnia]

thank you iluvme!

so yet another question..
Use your calculator to convert the following angles to degrees giving your answer to nearest 0.1 degree.
(i)0.46^c
(ii)(root)3^c

havnt done this in school i dont know why?!! :S but its theres in textbook :/

[iluvme]

Welcome

It would help if you remember that 1 radian= 180/pie

[Amii]

I don't take Maths- it's my friend's doubt

Find the range of values of p for which the roots of the equation px2+px-2=0

The answer given is p<= -8. According to her the answer is supposed to be p< -8 and p >0

Could someone please help?

Thank you