physics doubt

[nid404]

but its written in the Que's to treat the whole line as straight!!!

treating XY to be straight only for the calculation of the area of the trapezium...not otherwise (if u extend the rest of the line it wouldn't be close to XY)

[sweetie]

ok... Thank You
can u help me in Q9 of may04

[nid404]

s= v² sin 2theta / g    tan theta=1.25/10
 10= v² sin (2X7.125)/ 9.8
  v²= 10/ 0.025=398.125
       v = root of 398.125= 20

[T.Q]

ok... Thank You
can u help me in Q9 of may04

ANOTHER WAY

uy=0

so  , s=0.5gt^2

t= (1.25/0.5g)^0.5

t= 0.51 s

v= d/t

v=10/0.51

v= 19.8 ms-1

so the answer is D

[sweetie]

thanx sooo much nid and T.Q
+rep

[halosh92]

u guys could u please help me out in this paper:
paper 1 2002 nov.
Q15
q17
q22
q28
q35
q36
please explain in details thxxx aloot

[nid404]

u guys could u please help me out in this paper:
paper 1 2002 nov.
Q15
q17
q22
q28
q35
q36
please explain in details thxxx aloot

that's a lot of them...
will take some time

[Saladin]

Let me do the first half.

15: A. Because the diagonal is longer than both the other forces. Thus, it is the hypotenuse. And, the forces are all 90 degress from each other. It is like the end of a box.

17: D. There is no acceleration, so no change in kinetic energy and there for D.

22: A. Solid and liquids have the same densities and the same molecular spacing. The answer is not b, because that would imply that solids have a desnity 1000 times greater than liquids.

28: B. Increasing wavelength means that the chances of interaction decreases, and thus they are further apart.

Nid can do the rest. g2g

[nid404]

Q15) A obv  resultant vector x and y components
Q17) D  no change in velocity, therefore no change in k.e
Q22) Density and molecular spacing in solids and liquids is approx the same...hence A
Q28) lambda= ax/ D where a is the distance between the slits, x the distance between the fringes and D is the distance between the slit and screen. to increase separation that is x..
A-> if f is increased means lambda is decreased as v=flambda.....so this is out(cuz lamda and x are directly proportional)
B->lamda increased ...then x will increase...so B
C->decreasing D will reduce x (directly proportional)
D-> increasing a will reduce x (inversely proportional

Q35) R increases with length... so pointer will be moved to Y. But this will cause I=0...V=IR  so V=0
Q36) in the  parallel wire with the 5ohm resistors, 2V is split equally, so potential between source and X= 2/3 source and Y= 2X2/3=4/3
difference is 2/3  which is A

[nid404]

thanks for offering help dude...but im done...

[Saladin]

thanks for offering help dude...but im done...

U did get a head start though.

[sweetie]

cud sum1 xplain Q5 of may03?

[sweetie]

Q15) A obv  resultant vector x and y components
Q17) D  no change in velocity, therefore no change in k.e
Q22) Density and molecular spacing in solids and liquids is approx the same...hence A
Q28) lambda= ax/ D where a is the distance between the slits, x the distance between the fringes and D is the distance between the slit and screen. to increase separation that is x..
A-> if f is increased means lambda is decreased as v=flambda.....so this is out(cuz lamda and x are directly proportional)
B->lamda increased ...then x will increase...so B
C->decreasing D will reduce x (directly proportional)
D-> increasing a will reduce x (inversely proportional

Q35) R increases with length... so pointer will be moved to Y. But this will cause I=0...V=IR  so V=0
Q36) in the  parallel wire with the 5ohm resistors, 2V is split equally, so potential between source and X= 2/3 source and Y= 2X2/3=4/3
difference is 2/3  which is A

for Q36> why do u consider the resistance of X and Y from the source, why not the 3 resistors directly between X and Y ( 2 from the first path and 1 from the second)

[nid404]

huh...how 2 and 1.??
please explain what you are trying to say

[halosh92]

thankyou so muchhhhhhhhhhhhhhh nid and dude 321
rili appreciate it
+ rep