Author Topic: C1 Edexcel Jan2010 Question! Please help!  (Read 4544 times)

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #15 on: April 26, 2010, 12:07:06 pm »
whats the "?" in ur question?

Offline halosh92

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #16 on: April 26, 2010, 12:57:54 pm »
Giving your answers in terms of pie, solve the equation
3 tan2 thita - 1=0
for thita in the interval ?pie ? thita ? pie
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Offline halosh92

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #17 on: April 26, 2010, 12:58:59 pm »
(a) Given that t = log3 x, find expressions in terms of t for
(i) log3 x2,
(ii) log9 x.
(b) Hence, or otherwise, find to 3 significant figures the value of x such that
log3
x2 ? log9 x = 4.

how to do part aii
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nid404

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #18 on: April 26, 2010, 01:29:59 pm »
Giving your answers in terms of pie, solve the equation
3 tan2 thita - 1=0
for thita in the interval -pie < thita < pie

tan 2 theta= 1/3
2 theta= tan inverse of 1/3
2 theta= 18.4
theta=9.22
period of tan 2theta= +-90 [2theta right...so it will be half the tan theta period...1/2 of 180]
       = 9.22, 99.22, -80.78, -170.78
« Last Edit: April 26, 2010, 01:33:42 pm by nid404 »

Offline T.Q

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #19 on: April 26, 2010, 01:51:44 pm »
(a) Given that t = log3 x, find expressions in terms of t for
(i) log3 x2,
(ii) log9 x.
(b) Hence, or otherwise, find to 3 significant figures the value of x such that
log3
x2 ? log9 x = 4.

how to do part aii

for part aii

change the base

and make it 3

so it will be like this   (log3 x) /(log3 9)

so log3 x = t

and log3 9 = 2

so the answer is (1/2 t)
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Offline astarmathsandphysics

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #20 on: April 26, 2010, 01:52:57 pm »
(a) Given that t = log3 x, find expressions in terms of t for
(i) log3 x2,
(ii) log9 x.
(b) Hence, or otherwise, find to 3 significant figures the value of x such that
log3
x2 ? log9 x = 4.

ai)2t
ii)log9 x =lig3 x^(1/2) =1/2 t
retype qb

Offline halosh92

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #21 on: April 26, 2010, 02:07:42 pm »
for part aii

change the base

and make it 3

so it will be like this   (log3 x) /(log3 9)

so log3 x = t

and log3 9 = 2

why cant we use the inverse rule here....like make it 1/log x3 ...............where log x3=1/t ??????
which rule did u use there exactly....... how did u derive the base as 3 in (log3 x) /(log3 9)

so the answer is (1/2 t)
everyday we wake up is a miracle, then how do we say miracles dont happen?????

Offline T.Q

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #22 on: April 26, 2010, 02:24:35 pm »



i used this rule  

so log9 x = log x /log 9  , then u put any  base u want , i chose 3
« Last Edit: April 28, 2010, 09:51:14 am by T.Q »
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Offline halosh92

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #23 on: April 26, 2010, 02:33:19 pm »

i used this rule  

so log9 x = log x /log 9  , then u put any  base u want , i chose 3

thankyou :)
« Last Edit: April 28, 2010, 09:52:11 am by T.Q »
everyday we wake up is a miracle, then how do we say miracles dont happen?????

Offline halosh92

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #24 on: April 27, 2010, 07:35:03 pm »
people
could anyone do q7c
plzzz urgentttt
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Offline astarmathsandphysics

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #25 on: April 27, 2010, 08:23:20 pm »
a=129 r=114/120=0.95
ar^(n-1)<60
120*0.95^n<60
log120 +n log 0.95 < log 60
n?(log 60 -log 120)/log 0.95 =13.52
n=14

Offline halosh92

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #26 on: April 27, 2010, 08:32:29 pm »
Q4
plz explain in detailsss
thx alotttt
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Offline astarmathsandphysics

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #27 on: April 27, 2010, 09:06:04 pm »
or you could just keep miultiplying 120 by 0.95 until your answer is less that 60

Offline halosh92

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #28 on: April 27, 2010, 09:15:14 pm »
or you could just keep miultiplying 120 by 0.95 until your answer is less that 60

why do we do that?
could u be more specific plz?
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nid404

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Re: C1 Edexcel Jan2010 Question! Please help!
« Reply #29 on: April 28, 2010, 08:55:06 am »
Q4
plz explain in detailsss
thx alotttt

Do you need the a) part as well? (i mean the curve)

b) sin-10.35= x-30
    x=20.5o+30
     =50.5o




« Last Edit: April 28, 2010, 09:01:13 am by nid404 »