New servers, hooraaaay! More bandwidth, more power.
Giving your answers in terms of pie, solve the equation3 tan2 thita - 1=0for thita in the interval -pie < thita < pie
(a) Given that t = log3 x, find expressions in terms of t for(i) log3 x2,(ii) log9 x. (b) Hence, or otherwise, find to 3 significant figures the value of x such thatlog3x2 ? log9 x = 4.how to do part aii
for part aiichange the base and make it 3so it will be like this (log3 x) /(log3 9)so log3 x = tand log3 9 = 2why cant we use the inverse rule here....like make it 1/log x3 ...............where log x3=1/t which rule did u use there exactly....... how did u derive the base as 3 in (log3 x) /(log3 9)so the answer is (1/2 t)
i used this rule so log9 x = log x /log 9 , then u put any base u want , i chose 3
or you could just keep miultiplying 120 by 0.95 until your answer is less that 60
Q4plz explain in detailsssthx alotttt