I have done the mj 2003 q9 and the mj 2002 q8 (i) correctly.
But I still can't get the answer for q8 part (ii).
Since the new plane contains line l and it is perpendicular to p
[and by letting normal of the new plane to be (ax+by+cz)],
(3,-1,2).(a,b,c)=0 and (1,3,-2).(a,b,c)=0
I came up with two equations ; 3a-b+2c=0 --(1) and a+3b-2c=0 --(2)
and when I solve them simultaneously,all interms of b, i got (a,b,c) = (-1/2b,b,5/4b)
and then here is where i stucked. I need more help on here.
By the way, Thank you very much astar for your help . What an interesting site you have there!
It is very very helpful for me