Author Topic: M1 HELP NEEDED, RIGHT NOW!!  (Read 3948 times)

Offline mousa

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M1 HELP NEEDED, RIGHT NOW!!
« on: April 07, 2010, 06:08:26 pm »
Hello everyone, i need help with those couple of questions.
Please explain your steps in detail and clearly.

Q 7) ii .....Nov 2008

Q6) Nov 2004

Thanks.

nid404

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #1 on: April 07, 2010, 06:24:37 pm »
Nov 08
Q7

integrate acc, ull get velocity, integrate velocity, ull get distance...

double integration of (10 ? 0.3t)

v=dat=10t-0.3t2/2 +5
s=dvt= 10t2/2 - 0.3 t3/2X3 +5t
       = 5t2 - 0.3t3/6 + 5t
substitute t=2.5 (since 0.5sec taken to travel uptil A)
s=42.97
total s= 42.97+1.25
        =44.2m

nid404

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #2 on: April 07, 2010, 06:40:21 pm »
nov 2004

one of my fav qs

i) F<= uR
    <=0.75 8000
F<= 6000

ii) F max on top box= uR=.4 x4000=1600=400a a<=4

P-6000=3200
pmax=9200

Offline mousa

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #3 on: April 07, 2010, 07:19:06 pm »
nov 2004

one of my fav qs

i) F<= uR
    <=0.75 8000
F<= 6000

ii) F max on top box= uR=.4 x4000=1600=400a a<=4

P-6000=3200
pmax=9200


i am confused about the 2nd part, can you explain more?

nid404

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #4 on: April 07, 2010, 07:25:39 pm »
Fmax on top box<=1600
F=ma
hence a<=4

P-6000=ma
Pmax-6000=800X4
P=3200+6000
=9200

If there has to be no slipping in the system, both should move together....and that will happen only when they both have the same accn

Offline mousa

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #5 on: April 07, 2010, 07:36:14 pm »
Fmax on top box<=1600
F=ma
hence a<=4

P-6000=ma
Pmax-6000=800X4
P=3200+6000
=9200

If there has to be no slipping in the system, both should move together....and that will happen only when they both have the same accn


Thank you niddy. :)

nid404

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #6 on: April 07, 2010, 07:36:40 pm »
no prob

Offline halosh92

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #7 on: April 08, 2010, 11:13:21 am »
could someone answer this plzzz rili urgent :S"
 a stone is dropped from the top of a tower. one second later another stone is throw vertically downwards
from the same point witha velocity of 14m/s .
if theyb hit the ground together find the height of the tower.

thx a ;Dloot
« Last Edit: April 08, 2010, 11:35:52 am by halosh92 »
everyday we wake up is a miracle, then how do we say miracles dont happen?????

nid404

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #8 on: April 08, 2010, 04:45:40 pm »
assuming the stone is of the same mass

s= ut+1/2 gt2
s=14(t+1)+ 1/2 g(t+1)2
equate the two

ut+1/2 gt2=14(t+1)+ 1/2 g(t+1)2    u=0
So
1/2 gt2=14(t+1)+ 1/2 g(t+1)2
find the value of t
substitute to get s

Offline halosh92

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #9 on: April 08, 2010, 05:00:45 pm »
assuming the stone is of the same mass

s= ut+1/2 gt2
s=14(t+1)+ 1/2 g(t+1)2
equate the two

ut+1/2 gt2=14(t+1)+ 1/2 g(t+1)2    u=0
So
1/2 gt2=14(t+1)+ 1/2 g(t+1)2
find the value of t
substitute to get s

thx a bunch man! life saver u r!
everyday we wake up is a miracle, then how do we say miracles dont happen?????

nid404

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #10 on: April 08, 2010, 05:29:44 pm »
Ur welcome

Offline halosh92

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #11 on: April 14, 2010, 01:16:55 pm »
hello
could someone help me with this question please!!!!!!!!!
m1 edexcel AS
jan 2009
Q3,b,c
everyday we wake up is a miracle, then how do we say miracles dont happen?????

Offline astarmathsandphysics

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #12 on: April 14, 2010, 04:55:56 pm »
2 hours

nid404

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #13 on: April 14, 2010, 05:00:00 pm »
hello
could someone help me with this question please!!!!!!!!!
m1 edexcel AS
jan 2009
Q3,b,c

put the paper up plz

Offline halosh92

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Re: M1 HELP NEEDED, RIGHT NOW!!
« Reply #14 on: April 14, 2010, 05:07:17 pm »
there u go
everyday we wake up is a miracle, then how do we say miracles dont happen?????