ANY DOUBTS HERE!!!

[Meticulous]

His morning = noon. Wake up A.F

Bleh

[nid404]

Bleh

haww 

[Meticulous]

haww 

Shorry.ok..umm..sorry

[nid404]

Shorry.ok..umm..sorry

wtv

[Meticulous]

wtv

haaaaaaww

[nid404]

haaaaaaww

we can't do this here...so shush 

[halosh92]

Initial momentum=0 so final momentum will also be equal to 0

2400XV-800v=0

opp directions.

2400V=800v
v/V=2400/800
v/V=3

Hope you got that now

hey nid i rili dont get this if it is v/V shouldnt it be 800/2400 ??
thx

[nid404]

hey nid i rili dont get this if it is v/V shouldnt it be 800/2400 ??
thx

ohkay wait

2400V-800v=0

2400V=800v

2400V/800=v
3V=v
3=v/V

does this help?

[Ghost Of Highbury]

Barge of m=4000Kg , pulled in a straight line by two boats with an acceleration of 0.6m/s^2.
The tension in one towrope is 1800N and in the other is 1650N. Given that the angles the reopes make with the direction of the motion are 20 degree and x degree respectively, find the value of x and Resistance to motion .

Answer --> As the angle is inversely proportional to the force, i used the inverse proportion concept to find the
                x-angle. like this

               1800 -> 20
               1650 --> x

 x = (20*1800)/1650 = 21.9 degrees (correct answer)

i used this x value to calculate the resistance and i got the correct answer.

---------------MY DOUBT----------------------------

i was wondering , is there any other way to find the x angle?

PS : Diagram attached.

Correct me if im wrong.

thank you.

[halosh92]

ohkay wait

2400V-800v=0

2400V=800v

2400V/800=v
3V=v
3=v/V

does this help?

YES ALOOT
thx a bunch 

[halosh92]

sure A.F np.
june 2008 Q6b physics
with explanation plzzzzz

could u do this as well ?

[nid404]

Barge of m=4000Kg , pulled in a straight line by two boats with an acceleration of 0.6m/s^2.
The tension in one towrope is 1800N and in the other is 1650N. Given that the angles the reopes make with the direction of the motion are 20 degree and x degree respectively, find the value of x and Resistance to motion .

Answer --> As the angle is inversely proportional to the force, i used the inverse proportion concept to find the
                x-angle. like this

               1800 -> 20
               1650 --> x

 x = (20*1800)/1650 = 21.9 degrees (correct answer)

i used this x value to calculate the resistance and i got the correct answer.

---------------MY DOUBT----------------------------

i was wondering , is there any other way to find the x angle?

PS : Diagram attached.

Correct me if im wrong.

thank you.

Yes aadi ...what you've done is not ideally the correct way.

Resolve the forces vertically. There is no vertical motion...so no resultant vertical force

1650 sinx= 1800sin20

[nid404]

could u do this as well ?

yup

I've explained this a lot many times before It's long stuff...ill look for it

[nid404]

here


1) When S1 is open, the circuit is not a closed one and hence not functional. Power will thus be 0
2) When only S3 is open, Current flows through A and wire with S2...power of each heating element is given as 1.5kW(stated in the question)...so in this case it is that of A. Current doesn't flow through B because it offers more resistance than wire with S2.
3)when all switches r closed...No current flows through B. You must know that any charge will take the path with least resistance....
So when S2 is closed, current flows through the wire with S2 since it offers a lesser resistance in comparison with wire with heating element B. So Power would be that of A nd C= 1.5+1.5=3kW
4)When only S1 is closed, Current flows through A and B...combined Resistance is 76.8ohms...I=3.125A..P=I2R =0.75kW
5)When only S2 is open, current flows through all the heating elements A, B and C.
A and B in series= 76.8ohms
With C in parallel
So combined R
1/R= 1/76.8+1/38.4
R=25.6
I=240/25.6=9.375
P=9.3752X25.6=2.25kW

[halosh92]

here


1) When S1 is open, the circuit is not a closed one and hence not functional. Power will thus be 0
2) When only S3 is open, Current flows through A and wire with S2...power of each heating element is given as 1.5kW(stated in the question)...so in this case it is that of A. Current doesn't flow through B because it offers more resistance than wire with S2.
3)when all switches r closed...No current flows through B. You must know that any charge will take the path with least resistance....
So when S2 is closed, current flows through the wire with S2 since it offers a lesser resistance in comparison with wire with heating element B. So Power would be that of A nd C= 1.5+1.5=3kW
4)When only S1 is closed, Current flows through A and B...combined Resistance is 76.8ohms...I=3.125A..P=I2R =0.75kW
5)When only S2 is open, current flows through all the heating elements A, B and C.
A and B in series= 76.8ohms
With C in parallel
So combined R
1/R= 1/76.8+1/38.4
R=25.6
I=240/25.6=9.375
P=9.3752X25.6=2.25kW

thankyou