Qualification > Queries
ANY DOUBTS HERE!!!
nid404:
--- Quote from: sweetie on April 27, 2010, 09:22:48 pm ---more Que's in chem.
may02, P1 (CIE)
Q6,21,11
--- End quote ---
Q6) P1V1+P2V2= P3V3
he (1X2) + ne (2X1)= x X 3
x= 4/3
A
What you do is take a V3= 3dm3 (1dm3 of he and 2 dm3 of ne..since they are connected)
Q11) C
It will keep increasing as more products are formed...later, reactants act as a limiting agent...
If you are wondering why the curve can't plateau out, it is because no more substrate has been added to keep the rate constant....as the conc of substrate falls, rate of reaction falls
Q21) You already had 6 as soon as you figure the formula...right?
now when the haloalkane is either one of these C2H4Cl2 or C2H2Cl4 or C2H3Cl3, they could have isomers...
in C2H4Cl2 the Cl could be on each carbon or only on 1 carbon...2 possible structures
C2H2Cl4 the Cl could be 2 on each carbon or 3 on 1 and 1 on the other
C2H3Cl6 the Cl could be all 3 on one, or divide as 2 on 1 and 1 on the other
6+ the 3 possibilities = 9
C
~ A.F ~:
Awesomeness Nid..
+rep. :)
nid404:
:-[ :-[
Thank You :)
sweetie:
Thank You nid..
+rep
nid404:
--- Quote from: sweetie on April 28, 2010, 11:22:09 am ---Thank You nid..
+rep
--- End quote ---
ur welcome :)
Navigation
[0] Message Index
[#] Next page
[*] Previous page
Go to full version