Qualification > Queries
ANY DOUBTS HERE!!!
Saladin:
Hey u guys, post all ur doubts here, and I will do my best to answer them form u.
Just trying out the tex editor.
Sue T:
i hope chemistry doubts go here as well
past paper says:
The equilibrium constant, Kc, for the reaction to form ethyl ethanoate from ethanol and ethanoic
acid, C2H5OH + CH3CO2H CH3CO2C2H5 + H2O, at 60(degree)C is 4.00.
When 1.00 mol each of ethanol and ethanoic acid are allowed to reach equilibrium at 60(degree)C, what
is the number of moles of ethyl ethanoate formed?
A 1/3
B 2/3
C 1/4
D 3/4
3ishakay:
--- Quote from: Sue T on April 06, 2010, 04:55:15 pm ---i hope chemistry doubts go here as well
past paper says:
The equilibrium constant, Kc, for the reaction to form ethyl ethanoate from ethanol and ethanoic
acid, C2H5OH + CH3CO2H CH3CO2C2H5 + H2O, at 60(degree)C is 4.00.
When 1.00 mol each of ethanol and ethanoic acid are allowed to reach equilibrium at 60(degree)C, what
is the number of moles of ethyl ethanoate formed?
A 1/3
B 2/3
C 1/4
D 3/4
--- End quote ---
hey ... dyu noe the anser to tht?
wht paper ist frm?
im thinkn the anser is B = 2/3
this is how i did it ..(any1 tell me if i got it wrong .. plz!!)
ethanol + ethanoic acid -----> ethylethanoate + water
C2H5OH + CH3CO2H -------> CH3CO2C2H5 + H2O
b4 eq. 1 1 0 0
aftr eq. 1-x 1-x x x
thn Kc= [ethylethanoate][water]
-----------------------
[ethanol][ethanoic acid]
so its like
[ x]^2 = 4
--------
[1-x]^2
thn u ju solv it like in maths ..
and thn u get 2/3 =D
rechek the smae crap..
go
( 2/3)^2 = 4!! TADA!!! :D:D:D
----------
(1/3)^2
nid404:
hey Thanks :)
3ishakay:
--- Quote from: nid404 on April 06, 2010, 06:05:15 pm ---hey Thanks :)
--- End quote ---
not a prbm 8) ;)
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