Qualification > Queries
ANY DOUBTS HERE!!!
nid404:
--- Quote from: ~ A.F ~ on May 31, 2010, 12:42:33 pm ---haaaaaaww :( :P
--- End quote ---
we can't do this here...so shush :P
halosh92:
--- Quote from: nid404 on May 31, 2010, 10:54:03 am ---Initial momentum=0 so final momentum will also be equal to 0
2400XV-800v=0
opp directions.
2400V=800v
v/V=2400/800
v/V=3
Hope you got that now :)
--- End quote ---
hey nid i rili dont get this if it is v/V shouldnt it be 800/2400 ??
thx ;)
nid404:
--- Quote from: halosh92 on May 31, 2010, 01:07:11 pm ---hey nid i rili dont get this if it is v/V shouldnt it be 800/2400 ??
thx ;)
--- End quote ---
ohkay wait
2400V-800v=0
2400V=800v
2400V/800=v
3V=v
3=v/V
does this help?
Ghost Of Highbury:
Barge of m=4000Kg , pulled in a straight line by two boats with an acceleration of 0.6m/s^2.
The tension in one towrope is 1800N and in the other is 1650N. Given that the angles the reopes make with the direction of the motion are 20 degree and x degree respectively, find the value of x and Resistance to motion .
Answer --> As the angle is inversely proportional to the force, i used the inverse proportion concept to find the
x-angle. like this
1800 -> 20
1650 --> x
x = (20*1800)/1650 = 21.9 degrees (correct answer)
i used this x value to calculate the resistance and i got the correct answer.
---------------MY DOUBT----------------------------
i was wondering , is there any other way to find the x angle?
PS : Diagram attached.
Correct me if im wrong.
thank you.
halosh92:
--- Quote from: nid404 on May 31, 2010, 01:10:07 pm ---ohkay wait
2400V-800v=0
2400V=800v
2400V/800=v
3V=v
3=v/V
does this help?
--- End quote ---
YES ALOOT
thx a bunch ;D ;D
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