Sorry, here it is: http://www.freeexampapers.us/IGCSE/Physics/CIE/2009%20Nov/0625_w09_qp_31.pdf
I don't understand how it is worked out.
10ai) Step up transformer obviously.
aii) Less current, less electrical energy lost, less heat energy given out
b) P = V*I, I = 55k/22k = 2.5
c) Rate of loss formula, P = I^2R = 2.5^2*3 = 18.75
d) The overall voltage reduced from 22K Volts due to the resistance of the wire, till it reaches the receiving end.
I know this is confusing sh*t, it had appeared in my paper! nov 09! V = 2.5*3 = 7.5
from wiki "For example, an electric space heater may very well have a resistance of ten ohms, and the wires which supply it may have a resistance of 0.2 ohms, about 2% of the total circuit resistance. This means that 2% of the supplied voltage is actually being lost by the wire itself."
e) 22000 - 7.5 -7.5 = 21985 (2 times 7.5 because there are two wires, each voltage dorp = 7.5)