Author Topic: ALL PHYSICS DOUBTS - POST HERE !!  (Read 228399 times)

holtadit

  • Guest
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #750 on: May 11, 2010, 08:57:36 am »
im doing physics p6 at 3 in ksa!!!!
its 10:30 now,,,im nervous!!! :-\ :-\


Its one of the easiest Paper 6’s ever. I just finished it.


DON’T ask me any questions about whats coming as that would be against the rules.

Offline Fastal

  • SF Citizen
  • ***
  • Posts: 181
  • Reputation: 341
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #751 on: May 11, 2010, 09:05:01 am »
i finished around 3 hours ago, it was sh*t easy

Offline Adzel

  • SF Citizen
  • ***
  • Posts: 230
  • Reputation: 272
  • ALLAH IS THE GREATEST
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #752 on: May 11, 2010, 09:15:58 am »
Same to me...already done...very easy Al7amdullah.

Offline $H00t!N& $t@r

  • SF Geek
  • ****
  • Posts: 323
  • Reputation: 887
  • Gender: Female
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #753 on: May 11, 2010, 09:29:44 am »
It's good to see guy so relaxed. I hope i can say the say after the exam which is in like... 4 hours from now!
Good luck every1 for the physics exam and the ones after this!
"If A equals success, then the formula is:
A=X+Y+Z, X is work. Y is play. Z is keep your mouth shut"- Albert Einstein

Offline Vin

  • SF V.I.P
  • ********
  • Posts: 7914
  • Reputation: 52609
  • Gender: Male
    • Theory of Life - A new skew.
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #754 on: May 11, 2010, 09:32:24 am »
"An electron beam is equivilent to an electric current, but without the wire. It can bla bla bla.... In this diagram, the magnetic field is at right angles to the electron beam, so the beam is deflected."
This is what my book says... but how come the electrons go down (srry for bad quality). If u use Flemingooo's left hand rule, the current is ur middle finger(so points to the left [direction of electrons]), the field is ur second finger (pointing into the paper[direction of magnetic field]) and so ur thumb will be pointing up, which shows how the electrons will be deflected...How come they show it going down?

YA so it is right !! it is supposed to go down .. check again !! index finger diagonally up .. middle finger pointing left .. thumb down !!


Offline Baladya

  • meawwwww hao hao >.<
  • SF Geek
  • ****
  • Posts: 554
  • Reputation: 681
  • Gender: Male
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #755 on: May 11, 2010, 09:50:28 am »
YA so it is right !! it is supposed to go down .. check again !! index finger diagonally up .. middle finger pointing left .. thumb down !!



ya but in the book its going to the right... Magentic field in the paper, movement down. (its just the camera changed it). So how?
Looks like i ran out of cool signatures :|

Offline Vin

  • SF V.I.P
  • ********
  • Posts: 7914
  • Reputation: 52609
  • Gender: Male
    • Theory of Life - A new skew.
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #756 on: May 11, 2010, 09:59:15 am »

I think they might hav considered the beam of electron as a conventional current in the opposite direction .. which book is it ..By the way ??

Offline Ghost Of Highbury

  • O_o_O lala!
  • SF Farseer
  • *******
  • Posts: 4096
  • Reputation: 41428
  • Gender: Male
  • Namaskaram!
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #757 on: May 11, 2010, 10:02:59 am »
yes i remember this q, our sir told us that wenever an electron beam is given, point ur current finger to the opposite direction, like here, if its pointing left, point it to the right. i dont exactly remember the reason, ill try n get back

yes, its about the conventional current..
divine intervention!

Offline Baladya

  • meawwwww hao hao >.<
  • SF Geek
  • ****
  • Posts: 554
  • Reputation: 681
  • Gender: Male
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #758 on: May 11, 2010, 10:04:25 am »
Makes sense Aodi :D Thanks ;)
Vin its the IGCSE Collin thingy book :D
Looks like i ran out of cool signatures :|

Offline Vin

  • SF V.I.P
  • ********
  • Posts: 7914
  • Reputation: 52609
  • Gender: Male
    • Theory of Life - A new skew.
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #759 on: May 11, 2010, 10:13:57 am »

Oh i hate collins .. dunno abt phy but i hate its chemistry .. can u believe its thinner thn my notebook !!

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #760 on: May 11, 2010, 10:16:07 am »
cos electrons and conventional current have opposite charge

Offline Baladya

  • meawwwww hao hao >.<
  • SF Geek
  • ****
  • Posts: 554
  • Reputation: 681
  • Gender: Male
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #761 on: May 11, 2010, 11:03:36 am »
Oh i hate collins .. dunno abt phy but i hate its chemistry .. can u believe its thinner thn my notebook !!

It has nothing in it...
Looks like i ran out of cool signatures :|

Offline Baladya

  • meawwwww hao hao >.<
  • SF Geek
  • ****
  • Posts: 554
  • Reputation: 681
  • Gender: Male
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #762 on: May 11, 2010, 11:06:33 am »
Hey VIN. I asked u a question b4 and u said for accelerating objects u do this formula: 0.5ta (timeXacceleration) K but why the 0.5????????????
Looks like i ran out of cool signatures :|

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #763 on: May 11, 2010, 11:09:47 am »
1/2 at^2
The 1/2 is cos accelerations is from rest
on a velocity time graph the distance is area under curve - a triangle so area =1/2base*height hence the 1/2

Offline Ghost Of Highbury

  • O_o_O lala!
  • SF Farseer
  • *******
  • Posts: 4096
  • Reputation: 41428
  • Gender: Male
  • Namaskaram!
Re: ALL PHYSICS DOUBTS - POST HERE !!
« Reply #764 on: May 11, 2010, 11:10:36 am »
To calculate the distance of accelerating objects use this formula

Distance = ut + \frac{1}{2}at^2

u = inital velocity

v = final velocity

t = time

a = acceleration

u is generally -, so the formula boils down to

Distance = \frac{1}{2}at^2

1/2 = 0.5

Therefore,

Distance = 0.5at2
divine intervention!