new doubts...
Both questions r from Nov 2008:
1) Q5(c) Using a 40W heater, 16.3g of ice is melted in 2 minutes. The heater is then switched off. In a further 2 minutes, 2.1g of ice is melted.
Calculate the value of specific latent heat of fusion of ice from these results.
2) Q6(b) What's the formula for the refractive index? sinr/sini or sini/sinr? Which is the incident and refracted ray? :S
heat is gained from the surroundings in the experiment, by measuring for another two minutes, you can work out the effect of heat gained from the surroundings (ice that were melted due to those heat), subtract that from the total amount of ice melted will get you the full amount of ice melted due to the energy supplied by the heater.
Specific latent heat of fusion = ML
40 x 120 = (16.3 - 2.1) L
L = 338 J / g
n = sin i / sin r (from rarer to denser medium. if it is from denser to rarer medium, such as glass to air, then take the reciprocal, sin r / sin i)