Author Topic: Chemistry P1 doubts  (Read 721 times)

Offline sweetie

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Chemistry P1 doubts
« on: March 31, 2010, 03:19:40 pm »
Nov05 p1( AS)

Q1> I GOT 27MOLES, but thats not the answer ( correct ans. is 13.5)
Q5.> isnt it suppose to be N2 because it has strong triple bond, so y is da ans HCl??
Q7. plz xplain
Q16> why is the ans. not D OR B???
Q17> whats a ligand??
Q19> i got that da carbon atom to which an "OH" grp is attached is one chiral centre, where is the other one ( da ans. says "B')
Q.24> plz xplain
Q25> Is the answer "D" not "A" because the aldehyde grp alone doesnt react with PCl5?
plz reply ASAP...
Thanx in advance :D

Offline tmisterr

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Re: Chemistry P1 doubts
« Reply #1 on: April 05, 2010, 12:02:33 pm »
Q1: write out the chemical equation, and then balance it its the easiest way
 Pb(C2H5)4+ 13.5O2 ---> 8CO2 + 10H2O + PbO Once you balance you can clearly see that you need 13.5 moles of oxygen to react.

Q5: It is HCL because an ideal gas should have no intermolecular forces of attraction. The triple bond you are thinking of is interatomic, not intermolecular. N2 has week Van der Waals intermolecular forces but HCL has permanent dipole dipole forces which are stronger than Van der Waals forces so it is the most likely.

Q7: A. This is because for neutralisation, the ionic equation is H+ + OH- ---> H2O. This is what causes the enthalpy change, and the stronger the acid and base, the more exothermic the reaction. P has to be a weak acid (ethanoic acid) because the enthalpy change is less than neutralisation of HCL with NaOH. Q has to be a weak base because the enthalpy change is less that HCL with a strong base (NaOH) of it has to be ammonia. And R has to be a strong base because the enthalpy change is the same as that of HCL and NaOH. since nitric acid is also a strong acid, you need a strong base, potassium hydroxide.

Q16: I will get back to you on this one

Q17: Definition of a ligand is the atome, ion or molecule which is bonded with dative covalent bonds to the central atom or ion in a complex. answer is B because ammonia is bonded to the central silver ion the complex formula is [Ag(NH3)]3+

Q19: the other is the one left of that one.

Q24: A. butan-2-ol can be dehydrated to form but-1-ene and but-2-ene. but-2-ene can be cis or trans therefore making 3 different alkened.

Q25: A cannot be the answer cause the compound has to react with both PCL5 and 2,4-DNPH. The Y in X cannot reace with PCL5 because it is neither an alcohol or a carboxylic acid.

Offline sweetie

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Re: Chemistry P1 doubts
« Reply #2 on: April 08, 2010, 04:20:24 pm »
Thank You soooo much :)

 +rep ;)