write the following in simplest form involving only one trigonometric function
tanA/(sec^2A)-2
i tried to solve it as following
(sec^2A)=tan^2A+1
tan^2A+1-2
tan^2A-1
-(-tan^2+1)
tanA/-(-tan^2+1)
2tanA/-(-tan^2+1)
-2(1/2tan2A)
-tan2A
in the answers it says -1/2tan2a not -tan2a as i solved above wat did i do wrong