physics

[nid404]

no vertical resultant force....since 6.1cos35=5 N
horizontal comp= 6.1 sin 35= 3.5N

[ruby92]

could u explain in it a bit more detail
the horizontal component is cos rite?

[nid404]

but when theta is between the vertical and the tension....vertical will be cos theta

[halosh92]

2002 nov physics AS cie
paper 2
Q3b
shouldnt we consider the direction of the velocity in the formula???
and how did they know thats the time??

[ruby92]

M/j 2006 paper 2
5 c im basically stuck at the unit conversion part here  

6 C of the same paper

7 a, b

[astarmathsandphysics]

16N/cm=1600N/m
1/2*1600(0.06^2-0.045^2)+1/2*1600(0.03^2-0.045^)=1/2*0.85=v^2

[astarmathsandphysics]

0.5cm above top of tuve since w/2=16.2

[astarmathsandphysics]

7a C short circuit
A will blow if a power supply is use

[ruby92]

0.5cm above top of tuve since w/2=16.2

where did u get the 16.2 from?

o/n 2006
4 ii 1?

[halosh92]

2002 nov physics AS cie
paper 2
Q3b
shouldnt we consider the direction of the velocity in the formula???
and how did they know thats the time??

could solve this please?

[astarmathsandphysics]

16.2 is 32.4/2 half the wavelength

[nid404]

could solve this please?

Yes of course you consider the direction of motion.

check the attachment

momentum= 0.045X 4.2 - (0.045X -3.6) = 0.35 Ns

[halosh92]

Yes of course you consider the direction of motion.

check the attachment

momentum= 0.045X 4.2 - (0.045X -3.6) = 0.35 Ns

thxx aloot nid gr8 explanation!

[nid404]

Ur welcome mate

[ruby92]

this is from paper 2 CIE physics
i would really appreciate is someone would draw these graphs and post them here   

M/j 2004 2 b
 I need this ASAP