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Phosu:
10 Two spheres approach each other along the same straight line. Their speeds are u1 and u2
before collision, and v1 and v2 after collision, in the directions shown below.
before collision
 ->  <-
 O    O
 u1   u2

after collision
->   ->
 O    O
 v1   v2

Which equation is correct if the collision is perfectly elastic?
A u1 – u2 = v2 + v1
B u1 – u2 = v2 – v1
C u1 + u2 = v2 + v1
D u1 + u2 = v2 – v1

please explain, i ticked A, but the ans is D

astarmathsandphysics:
For perfectly elastic collision approach speed u1+u2=separations speed v2-v1

halosh92:

--- Quote from: astarmathsandphysics on March 26, 2010, 09:22:17 pm ---For perfectly elastic collision approach speed u1+u2=separations speed v2-v1

--- End quote ---

is this ALWAYS the formula ????
and could you please explain when do we use these formulas exactly?
very urgent plz and wat s speed of approach and separation anywway
thxx aloot
VERY URGENT PLZ

astarmathsandphysics:
Use the formula if you know a collision is perfectly elastic.
Speed of approach is the closing speed - add if they are moving towards each other, subtract if they are moving in the same direction.
Separation speed is the speed at which they are parting. Add if they are moving away from each other, subtract if they are moving in the same direction

Phosu:
The interference patterns from a diffraction grating and a double slit are compared.
Using the diffraction grating, yellow light of the first order is seen at 30° to the normal to the
grating.

The same light produces interference fringes on a screen 1.0 m from the double slit. The slit
separation is 500 times greater than the line spacing of the grating.

What is the fringe separation on the screen?

A 2.5 × 10^–7m
B 1.0 × 10^–5m
C 1.0 × 10^–3m
D 1.0 × 10^–1m

plz show how to solve,
i know the two formulas, but i dont know how to use them

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