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phys doubt

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halosh92:

--- Quote from: Phosu on March 26, 2010, 07:21:25 pm ---its A

--- End quote ---

i think its short circuiting  ??? so voltage is zero

astarmathsandphysics:
If you look v closely they are the same circuit

halosh92:

--- Quote from: astarmathsandphysics on March 26, 2010, 08:18:25 pm ---If you look v closely they are the same circuit

--- End quote ---

alright , in the question they say voltage is zero
how come????? is it liek each resistor in parallel to the other??

vanibharutham:
Wow, that was a fun question :P

took a while:

Heres how you do it,

You need to firstly work out the Resistance of the resistor from the first circuit...
BE CAREFUL WHERE THEY HAVE PLACED THE AMMETER...ITS ON THE PARALLEL CIRCUIT... so the total current in the circuit is 2 times the ammeter reading i.e. 2A

V = I R-total
6 = 2 x R-total
R-total = 3 ohms

Now use the resistance in parallel combination:

1 / R-total = 1/2R + 1/2R

you will get:

R-total = R

therefore,

each resistor has a value of 3 ohms



in the second circuit,

V = I R
6 = I ( 3 + 3)
I = 1.0 Amps


and voltmeter must read 0 Volts because there is no emf in the path across which the voltmeter is connected

halosh92:

--- Quote from: vanibharutham on March 26, 2010, 08:34:06 pm ---Wow, that was a fun question :P

took a while:

Heres how you do it,

You need to firstly work out the Resistance of the resistor from the first circuit...
BE CAREFUL WHERE THEY HAVE PLACED THE AMMETER...ITS ON THE PARALLEL CIRCUIT... so the total current in the circuit is 2 times the ammeter reading i.e. 2A

V = I R-total
6 = 2 x R-total
R-total = 3 ohms

Now use the resistance in parallel combination:

1 / R-total = 1/2R + 1/2R

you will get:

R-total = R

therefore,

each resistor has a value of 3 ohms



in the second circuit,

V = I R
6 = I ( 3 + 3)
I = 1.0 Amps


and voltmeter must read 0 Volts because there is no emf in the path across which the voltmeter is connected

--- End quote ---

THANKYOU ALOOOOTTT ;D ;D

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