Qualification > Math

A2 math cie HEEEEEELP!

<< < (2/3) > >>

astarmathsandphysics:
LHS=sin(3A) so 3A=arcsin(-sqrt(3)/2)=240, 300,600, 660
so solve 3A=240
2A=300
3A=600
3A=660

mayyoya92:
thank you very much but please could you explain the first part of your answer?

astarmathsandphysics:
x=arcsina then do 180-x, 360+x, 540-x,720+x etc

mayyoya92:
thank you very much! (i'm not so good at astc rules ::) ::)

mayyoya92:
is there any website having eplanation of astc rules? thanx in advance.

Navigation

[0] Message Index

[#] Next page

[*] Previous page

Go to full version