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A2 math cie HEEEEEELP!

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mayyoya92:
HI ,i just wanted some 1  to solve this logarithmic equation for me , i'm very bad at logarithms!!
if ln(x)+3 ln(y)-ln(2) = ln(x power 4)-ln(54)   ,fimd the value of x/y??
 thanx                                                         

mayyoya92:
oh thank you all ,i'm having great help here!! >:( >:( >:(

123:
Well whats so hard bout it??

>> ln(x)+3 ln(y)-ln(2) = ln(x^4)-ln(54)

here follow log rules     
eg. ln(a) + ln(b) = ln(ab) 
     ln(a) - ln(b) = ln(a/b)       
     3ln(a) = ln(a^3)                 

>> ln(x) + ln(y^3) -  ln(2) = ln(x^4) -ln(54)
    ln(x.y^3) - ln(2) = ln(x^4) -ln(54)

just collect all x & y on 1side and whole nos. on other side
i.e,
 -ln(2) + ln(54) = ln(x^4) - ln(x.y^3)
ln(54) - ln(2) = ln ([x^4] / [x.y^3]) 
ln(54/2) = ln(x^3 / y^3)
ln(27) = ln(x/y)^3

try to solve it urself, heres a hint:
ln(a)=ln(2)
a = e^2   ----->anti-log

hope this is helpful  :D

mayyoya92:
thank you very much ;D

mayyoya92:
another question about trignometry and astec rules,if 3A=2A +A prove that sin3A -4sin(power3)A ,hence solve the equation 3sinA-4sin(power3)A = -root3 /2...i know how to prove it but i can't solve it!!

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