forgot how q6 pg57 is done

I have done it b4, mayb try
resolving 2g vertically downwards (opposite to P & Q)
So for P & Q
P = 2gcos40
Q = 2gcos20
Though i don't think its simple as this!
Then q11 pg.58
Just resolve T & 2T vertically & horizontally
So
VERTICALLY: Tcos 60 + 2Tcos

going upwards but 50N going downwards
Tcos 60 + 2Tcos

= 50 ----------eq.1
HORIZONTALLY: T & 2T go in opposite directions: Tsin60 = 2Tsin

---------eq.2
For

from eq. 2
Tsin60 = 2Tsin

sin60/2 = sin


= sin^-1 (sin60/ 2)
u know

.....so find T from eq.1 !!
Hope this is right & clear
(PS: instead of a thanks plz give me +rep. power!!

)