Hello,
I attached a file ,,, could some1 please help me by writting the answers as i want to check them..
Thankyou in advance
since nobodys told u until now, so i thought i wud and i also saw some easy qs
, sorry but i cant answer all of them since im still doing igcse maths. neway ur answers--
a) i) V=15000-(2000*3)
=>£9000
ii)10000=15000-2000t
t=(10000-15000)/-2000
t=7 yrs
iii) this is because after 4 yrs the gradient does not remain constant and after 4 yrs the gradient does not remain -2000
b) i) 5000=18275e
-0.24t=>5000/18275=e
-0.24t=>t=5.4004 yrs
ii) % error=(error/actual value)*100
error=1700-[18275*e
-0.24*10]
error=£42.1294
=> % error=(42.1294/1700)*100
=> % error=2.4782%
c) i) i don't know
ii) £/yr
iii) the gradient represents the rate of decrease of the value of the car over time
d) i don't know
hope i helped