A fighter plane flying horizontally at an altitude of 1.5km with a speed of 720km/h passes directly overhead an anti-aircraft gun. At what angle from the vertical should the gun be fired for the shell with muzzle speed 60m/s to hit the plane?
the answe is 19.47', can u show the workings??
Coordinate of plane are(200t,1500)
coordinates of shell are (60tsinx, 60tcosx-0.5*9.8t^2)
hence
1500=60tcosx-0.5*9.8t^2 (1)
200t=60tsinx (2)
Are you sure the speed of the shell is 60m/s? It will never catch the plane?
I think it is 600
if it is then (2) becomes 200t=600tsinx so sinx=1/3 so x=sin^-1(1/3)=19.47 degrees