Qualification > Math
help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time :D)
SGVaibhav:
sorry i was away,
trying it now
this method is little different and making it little confusing
trying now
is there any such rule that sec x tan x should be > 0 or something
SGVaibhav:
ok got that part
confusion confusion confusion
in that site....
when they find the derivative of sec inverse for the range (pi/2) till pi.
they get a negative sign in the denomintor before the square root
how is that now
Tyserius:
--- Quote from: sgvaibhav on November 10, 2009, 05:11:45 pm ---ok got that part
confusion confusion confusion
in that site....
when they find the derivative of sec inverse for the range (pi/2) till pi.
they get a negative sign in the denomintor before the square root
how is that now
--- End quote ---
'Cause for cos x where pi/2 < x < pi, it is negative haha.
SGVaibhav:
this was truly confusing >:( :(
it will be very hard to explain.
but why do we need to care to put modulus
if there is no modulus, then the answer comes negatives (LET IT STAY NEGATIVE IF IT IS NEGATIVE >:()
annoying :-\
SGVaibhav:
yep one more thing
when sec goes negative, tan also goes negative
so negative x negative = positive
im going off pc now probably
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